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viva [34]
3 years ago
10

How to do it? Urgent ​

Physics
1 answer:
mixer [17]3 years ago
8 0

a)

F= ma

a=v/t

F=5*(35/5)

F=35N

b)

a=F/m

a=(35-2)/5

a=33/5

a=6.6N

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A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg
alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

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Magnification of lens, m = -\frac{v}{u}

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u = object distance

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Now,

1.90 = \frac{v}{u}

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}

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\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}

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A 5.0 kg object moving at 5.0 m/s. KE = mv2 times 1/2
steposvetlana [31]

Answer: KE = 62.5J

Explanation:

Given that

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Since kinetic energy is the energy possessed by a moving object, and it depends on the mass (m) of the object and the velocity (v) by which it moves. Therefore, the object has kinetic energy.

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