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3 years ago

How to do it? Urgent

Physics

1 answer:

mixer [17]3 years ago

8 0

F= ma

a=v/t

F=5*(35/5)

F=35N

a=F/m

a=(35-2)/5

a=33/5

a=6.6N

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You have a rock sample and analyze it for the presence of radioactive isotopes in order to determine when it was formed. You fin

Firdavs [7]

Answer:

the decay of half of the nuclei only a half-life has passed , b) in rock time it is 1 108 years

Explanation:

The radioactive decay is given by

N = N₀ $e^{\lambda t}$

If half of the atoms have decayed

½ N₀ = N₀ $e^{\lambda t}$

½ = $e^{\lambda t}$ ₀

Ln 0.5 = - λ t

t = - ln 0.5 /λ

The definition of average life time is

$T_{1/2}$ = ln 2 / λ

λ = ln 2 / $T_{1/2}$

λ = 0.693 / 100 10⁶

λ = 0.693 10⁻⁸ years

We replace

t = -ln 0.5 / 0.693 10⁻⁸

t = 10⁸ years

We see that for the decay of half of the nuclei only a half-life has passed

b) in rock time it is 1 108 years

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3 years ago

4. A desk with a mass of 10 kg is pushed across a floor with an acceleration of 4 m/s?. What

tatiyna

40 N. If you’re using F=MA MxA would be 10x4 which would get you 40 N

6 0

2 years ago

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Answer:

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Check all choices below that are correct. Increasing the frequency increases the current. Changing the frequency does not affect

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Two loudspeakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from the other. (a) What is the lowest fre

VMariaS [17]

Answer:

Explanation:

Given

Distance between two loud speakers $d=1.6\ m$

Distance of person from one speaker $x_1=3\ m$

Distance of person from second speaker $x_2=3.5\ m$

Path difference between the waves is given by

$x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}$

for destructive interference m=0 I.e.

$x_2-x_1=\frac{\lambda }{2}$

$3.5-3=\frac{\lambda }{2}$

$\lambda =0.5\times 2$

$\lambda =1\ m$

frequency is given by

$f=\frac{v}{\lambda }$

where $v=velocity\ of\ sound\ (v=343\ m/s)$

$f=\frac{343}{1}=343\ Hz$

For next frequency which will cause destructive interference is

i.e. $m=1$ and $m=2$

$3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda$

$\lambda =\frac{1}{3}\ m$

frequency corresponding to this is

$f_2=\frac{343}{\frac{1}{3}}=1029\ Hz$

for $m=2$

$3.5-3=\frac{5}{2}\cdot \lambda$

$\lambda =\frac{1}{5}\ m$

Frequency corresponding to this wavelength

$f_3=\frac{343}{\frac{1}{5}}$

$f_3=1715\ Hz$

8 0

3 years ago

How to do it? Urgent ​

How to do it? Urgent