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3 years ago

When discussing magnetic fields we could say that

2 answers:

6 0

When discussing magnetic fields we could say that metals can become magnetic if they have many spinning electrons that create magnetic fields.

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Kamila [148]3 years ago

3 0

<h3><u>Answers;</u></h3>

Metals can become magnetic if they have many spinning electrons that create magnetic fields.

<h3><u>Explanation</u>;</h3>

<em><u>Magnets are materials that have the capability of generating magnetic fields. </u></em>They repel non-magnetic materials such as wood, plastic etc. and attract magnetic material such as iron and steel.
<em><u>Magnetic materials such as iron and steel may be used to make magnets by the process of magnetization.</u></em> In these magnetic materials such as iron, cobalt and nickel,electrons spin in the same directions which makes the, magnetic but not yet magnets.
For metals to attain magnetism they have to be magnetized by having them enter the magnetic field of an existing magnet.

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Which non-mineral nutrients are essential in photosynthesis? (Select all that apply.) oxygen calcium hydrogen carbon

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Answer:

carbón, hydrogen and oxygen

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3 years ago

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4 years ago

A 15kg object strikes the ground with 2000J of kinetic energy after freely falling from rest. How far above the ground was the o

arsen [322]

Answer:

Explanation:

Find the final velocity at which it struck the ground by using the kinetic energy formula.

$KE=\frac{1}{2} mv^2$

$2000=\frac{1}{2} (15)v^2\\v=16.33$

Now use kinematics to solve for the vertical displacement. We were given the initial velocity and acceleration can be assumed to be 9.8

$V^2=V^2_i+2a(y_f-y_i)\\16.33^2=0^2+2(9.8)(y_f-y_i)$

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3 years ago

A train travels north at a speed of 50 m/s.

Gala2k [10]

The apparent velocity is B) 48 m/s north

Explanation:

Here we have a problem of relativity of velocities.

In fact, the train is travelling north at a speed of

$v_t = 50 m/s$

where this velocity is measured with respect to the ground.

At the same time, a passenger on the train is walking towards the rear (so, south) at a velocity of

$v'=2 m/s$

where this velocity is measured with respect to the train, which is in motion in the opposite direction.

Therefore, the apparent velocity of the passenger with respect to an observer standing on the ground is:

$v=V_t - v' = 50 - 2 = 48 m/s$

And the direction is north, since this number is positive.

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3 years ago

The end diastolic volume of a heart is 140 mL Assume that it is a sphere. At end diastole, the intraventricular pressure is 7mmI

Vera_Pavlovna [14]

Answer:

Explanation:

We know that, V = 140 mL = 0.00014 m3

Assume that it is a sphere. so, we have

V = (4/3) \pir3

r3 = (0.00014 m3) (3) / (4) (3.14)

r = \sqrt[3]{}\sqrt[3]{}3\sqrt{}3.34 x 10-5 m3

r = 1.93 x 10-7 m

(a) The wall tension at end diastole will be given as :

using a formula, we have

T = P r / 2 H

where, P = intraventricular pressure at end diastole = 7 mmHg = 933.2 Pa

H = wall thickness at this time = 0.011 m

then, we get

T = (933.2 Pa) (1.93 x 10-7 m) / 2 (0.011 m)

T = 8.18 x 10-3 N

(b) The wall tension at the end of isovolumetric contraction will be given as :

using a formula, we have

T = P r / 2 H

where, P = intraventricular pressure at end of isovolumetric contraction = 80 mmHg = 10665.7 Pa

H = wall thickness at this time = 0.011 m

then, we get

T = (10665.7 Pa) (1.93 x 10-7 m) / 2 (0.011 m)

T = 9.35 x 10-2 N

(d) The wall stress from A and B which will be given as :

we know that, \sigma = T / w

For part A, we have

\sigmaA = (8.18 x 10-3 N) / (0.011 m)

\sigmaA = 0.743 N/m

For part B, we have

\sigmaB = (9.35 x 10-2 N) / (0.011 m)

\sigmaB = 8.5 N/m

4 0

3 years ago