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mrs_skeptik [129]
3 years ago
12

A three-bend saddle will only fit tight if the radius of the obstruction is equal to or less than the radius of the bend.

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

True

Step-by-step explanation:

A three-bend saddle consists of a center bend and 2 side bends with the center bend having twice the angle of the side bends. Therefore, the radius of the obstruction has to be equal or less than the radius of the bend in order to fit tightly

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Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as
stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

a=7\ cm\\c=13\ cm

substitute

13^{2}=7^{2}+b^{2}

Solve for b

169=49+b^{2}

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

we have that

<em>Jayden's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\b=13\ cm

substitute and solve for c

7^{2}+13^{2}=c^{2}

49+169=c^{2}

218=c^{2}

c=\sqrt{218}\ cm

c=14.76\ cm

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\c=13\ cm

substitute

7^{2}+b^{2}=13^{2}

Solve for b

49+b^{2}=169

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

therefore

Sheridan's Work is correct

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3 years ago
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Answer:

88 > 9

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Step-by-step explanation:

< means Less Than

> means Greater Than

= means Equal to

Now,

88 > 9

59 > 41

157 < 174

18 < 129

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lions [1.4K]

Answer: mess

Step-by-step explanation:

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