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NemiM [27]
3 years ago
7

A seafloor plate slides under a continental plate during subduction. which type of plate boundary best describes this situation

Physics
1 answer:
Leto [7]3 years ago
5 0

Answer:

The situation where a seafloor plate slides under a continental plate during subduction is best described by convergent plate boundary.

Explanation:

The earth’s crust is broken down into tectonic plates that can move independently. They can interact in three different ways: converge (move toward one another), diverge (move away from one another) or transform (slide past one another). The three kinds of plate margins (boundaries where plates meet) are oceanic-oceanic, continental-continental, and continental-oceanic.

The regions where the plates are moving towards one another are known as convergent plate boundaries. During the convergence of continental and oceanic plates, the more-dense oceanic plate sinks below the less-dense continental plate and the oceanic plate is forced down further into the mantle. This is known as subduction. When the plate enters the mantle, the inside pressure breaks the rock. The broken rocks begins to melt from the heat due to the friction and as a result magma is formed. This magma rises toward the surface by breaking through the crust and forms a chain of volcanoes known as a volcanic arc such as the Cascade Mountains of North America and the Andes Mountains of South America.

During the convergence of two oceanic plates, one of the plates sinks underneath the other and forms an ocean trench (deep depression). The plate that sinks further down into the mantle starts to melt and as a result magma rises toward the surface and forms a chain of volcanic islands behind the ocean trench.

During the convergence of two continental plates, they buckle and compress to form complex mountains ranges of great height such as the Himalayas.

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a radio station broadcast a frequency 90500 Hz. these radio waves travel at speed of 30000 m/s. what is the wavelength of the ra
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Answer:

0.331m

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2 years ago
Michael Jordan, el célebre basquetbolista, ganó el torneo de clavadas de la NBA en 1988. Para lograr la hazaña saltó 1.35 metros
kozerog [31]

(a) 0.40 s

First of all, let's find the initial speed at which Jordan jumps from the ground.

The maximum height is h = 1.35 m. We can use the following equation:

v^2-u^2=2gh

where

v = 0 is the velocity at the maximum height

u is the initial velocity

g=-9.8 m/s^2 is the acceleration of gravity

Solving for u,

u=\sqrt{-2gh}=\sqrt{-2(-9.8)(1.35)}=5.14 m/s

The time needed to reach the maximum height can now be found by using the equation

v=u+gt

Solving for t,

t=\frac{v-u}{g}=\frac{0-5.14}{-9.8}=0.52s

Now we can find the velocity at which Jordan reaches a point 20 cm below the maximum height, so at a height of

h' = 1.35 - 0.20 = 1.15 m

Using again the equation

v'^2-u^2=2gh'

we find

v'=\sqrt{u^2+2gh}=\sqrt{5.14^2+2(-9.8)(1.15)}=1.97 m/s

And the corresponding time is

t'=\frac{v'-u}{g}=\frac{1.97-5.14}{-9.8}=0.32s

So the time to go from h' to h is

\Delta t = t-t'=0.52-0.32=0.20 s

And since we have also to take into account the fall down (after Jordan reached the maximum height), which is symmetrical, we have to multiply this time by 2 to get the total time of permanence in the highest 20 cm of motion:

\Delta t=2\cdot 0.20 = 0.40 s

(b) 0.08 s

This part is easier since we need to calculate only the velocity at a height of h' = 0.20 m:

v'^2-u^2=2gh'

v'=\sqrt{u^2+2gh}=\sqrt{5.14^2+2(-9.8)(0.20)}=4.74 m/s

And the corresponding time is

t'=\frac{v'-u}{g}=\frac{4.74-5.14}{-9.8}=0.04s

So this is the time needed to go from h=0 to h=20 cm; again, we have to take into account the motion downwards, so we have to multiply this by 2:

\Delta t = 2\cdot 0.04 =0.08 s

8 0
3 years ago
calculate the period of a wave whose frequency is 5 Hertz and whose wavelength is one centimeter give your answer in a decimal f
olga2289 [7]
The period of the wave is the reciprocal of its frequency.

       1 / (5 per second)  =  0.2 second .

The wavelength is irrelevant to the period.  But since you
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Wave speed = (frequency) x (wavelength)

                   = (5 per second) x (1cm)  =  5 cm per second
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3 years ago
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