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NemiM [27]
3 years ago
7

A seafloor plate slides under a continental plate during subduction. which type of plate boundary best describes this situation

Physics
1 answer:
Leto [7]3 years ago
5 0

Answer:

The situation where a seafloor plate slides under a continental plate during subduction is best described by convergent plate boundary.

Explanation:

The earth’s crust is broken down into tectonic plates that can move independently. They can interact in three different ways: converge (move toward one another), diverge (move away from one another) or transform (slide past one another). The three kinds of plate margins (boundaries where plates meet) are oceanic-oceanic, continental-continental, and continental-oceanic.

The regions where the plates are moving towards one another are known as convergent plate boundaries. During the convergence of continental and oceanic plates, the more-dense oceanic plate sinks below the less-dense continental plate and the oceanic plate is forced down further into the mantle. This is known as subduction. When the plate enters the mantle, the inside pressure breaks the rock. The broken rocks begins to melt from the heat due to the friction and as a result magma is formed. This magma rises toward the surface by breaking through the crust and forms a chain of volcanoes known as a volcanic arc such as the Cascade Mountains of North America and the Andes Mountains of South America.

During the convergence of two oceanic plates, one of the plates sinks underneath the other and forms an ocean trench (deep depression). The plate that sinks further down into the mantle starts to melt and as a result magma rises toward the surface and forms a chain of volcanic islands behind the ocean trench.

During the convergence of two continental plates, they buckle and compress to form complex mountains ranges of great height such as the Himalayas.

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irinina [24]

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5 0
2 years ago
A gun has a muzzle speed of 80 meters per second. What angle of elevation should be used to hit an object 180 meters away? Negle
olga55 [171]
Knowing the initial velocity and angle, the horizontal range formula is given by   R= V^2sin(2teta) / g, so we can get 
sin(2teta)=Rg/V^2
sin(2teta)= (180 x 9.8)/ 80^2= 0.27, sin(2teta)=0.27, 2teta=arcsin(0.27)=15.66, so teta=15.66/2

teta=7.83°
5 0
3 years ago
Read 2 more answers
An athlete needs to lose weight and decides to do it by “pumping iron.” (a) How many times must an 90.0 kg weight be lifted a di
Wittaler [7]

Answer:

230kg would be the best answer

Explanation:

7 0
3 years ago
A particle (mass = 2.0 mg, charge = −6.0 μC) moves in the positive direction along the x axis with a velocity of 3.0 km/s. It en
Virty [35]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The acceleration would be  a = 0.003* 6 =0.018\  m/s^2    

Explanation:

The objective of this solution is to obtain the acceleration of the particle

       Now looking at Newton law which is mathematically represented as

                       F = ma

  Where F is the force experience by a particle

              m is the mass of the particle

              a is the acceleration of the particle

  And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as

                    F = qvB

Where q is the charge of the particle

             v is the velocity of the  charge

             B is the magnetic field the charge is under it influence

  Now equating this two formulas

                   ma = qvB

 Making a the subject we have

                  a = \frac{qvB}{m}

In the question the direction of the is in the positive x-axis which is i hence the direction would be in the i direction

      So substituting  (2.0i +3.0j+4.0k)mT = (2.0i +3.0j+4.0k)*10^{-3}T for B

                    a = \frac{q}{m} * v (2.0i +3.0j +4.0k)*10^{-3}

      Substituting       3.0 Km /s = 3.0*10^{3}\ m/s  for v  and -6.0 \muC = -6.0*10^{-6} C for q

                     a = \frac{-6.0*10^{-6}}{2.0*10^{-3}} * 3.0*10^{3} *(2i+3j+4k) *10^{-3}

                       a = 0.003 * 3i(2i+3j+4k)

                      a = 0.003 *((3*2)i \ \cdot i \ +(3*3) i \ \cdot \ j  \ + (3*4)i \ \cdot \ k)

According to vector multiplication

                                             i \cdot i = j \cdot j = k\cdot k = 1\\\\and \ i\cdot j = i\cdot k  = 0

     So

               a = 0.003* 6 =0.018\  m/s^2          

     

8 0
3 years ago
What does the left y-axis show?
vivado [14]

Answer:

The correct option is;

a- sea surface temperature anomaly, in degrees Celsius

Explanation:

From the diagram related to the question we have two graphs super imposed of Sea surface temperature anomaly, in degrees Celsius and cholera incidence anomaly (%) both plotted against time in years.

On the left the y-axis represents the sea surface temperature anomaly while on the right, the y-axis represents the cholera incidence anomaly (%).

The display of the graph shows the sea surface temperature anomaly in blue.

6 0
2 years ago
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