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Shalnov [3]
3 years ago
15

Vertical analysis (common-size) percentages for Vallejo Company’s sales, cost of goods sold, and expenses are listed here.

Mathematics
1 answer:
dybincka [34]3 years ago
6 0
Cost of goods sold - expenses = net income
do this for each year and compare.
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The price of diesel is $1.479 per litre. It cost Steve $83.80 to top up his van with diesel. The fuel tank has a capacity of 95
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83.800 ÷ 1.479 = 56.65 ≈ 56.7 litres of diesel Steve buyed ;
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4 years ago
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an elk grove limo service costs $26 for a 6 mile trip and charges $58 for a 14 mile trip. whats the rate of change
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The rate of change is 4.3
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One dozen bananas weigh 3 pounds, how much do 2 bananas weigh?
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3 years ago
If x+y=10 and x-y =6 what is the answer of x cube - y cube fast​
AfilCa [17]

Answer:

x+y=10 which means that x=10-y

Replace 10-y in the other equation which gives you:

10-y-y=6

10-2y=6

-2y=-4

y=2

Replace 2 in any of the 2 equations same answer for both:

x+y=10

x+2=10

x=8

So,

{x}^{3} - y^{3}

=  {8}^{3}  -  {2}^{3}

=512-8

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Hope this helps!

4 0
3 years ago
A certain hereditary disease can be passed from a mother to her children. Given that the mother has the disease, her children in
uranmaximum [27]

Answer:

(a) P=0.694

(b) It is independent, beacuse the probability of having the disease for the children depends only on her mother condition (if she has the disease or not), not the condition of his brothers and sisters.

(c) P=0.25

Step-by-step explanation:

(a) If the mother has 0.33 probabilities of having the disease, the probability of the children having the disease is equal to the product of the probability of the mother having the disease (0.33) and the probability of inherit it (0.50).

So the probability of one child of having the disease is 0.33*0.5=0.167. The probability of not having the disease is then (1-0.167)=0.833

The probability of both children to not have the disease is 0.833^2=0.694.

(b) It is independent, beacuse the probability of having the disease for the children depends only on her mother condition (if she has the disease or not), not the ones of his brothers and sisters.

(c) If the mother has the disease, the child have a probability of 0.5 of having the disease.

The probability, given that the mother has the disease, of both child not having the disease is 0.5^2=0.25.

4 0
4 years ago
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