10. After sampling 16 members of a normal population you find the sample mean equals 20 and the sample standard deviation, s, eq
uals 4. Construct a 90% confidence interval estimate for μ.
a. 18.04-21.96
b. 18.25-21.75
c. 18.36-21.64
d. None of the above
1 answer:
Answer:
c. 18.36-21.64
Step-by-step explanation:
Using the following formulas the lower and upper limits of the interval are calculated
Lower limit = mean - (standard deviation /√sample size)* Zr
Upper limit = mean + (standard deviation /√sample size)* Zr
Zr depends on confidence interval
Zr for 90% = 1.645
then
Lower limit = 20 - (4 /√16)* 1.645 = 18.355 ≈ 18.36
Upper limit = 20 + (4 /√16)* 1.645 = 21.645 ≈ 21.64
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