The enthalpy of the reaction can be obtained from the enthalpies of formation as -16.2 kJ/mol.
<h3>What is the enthalpy of reaction?</h3>
We know that any time that there is a chemical reaction, there is an interaction that place between the reactants and the products and as such we are going to get new substances and these are the substances that I have referred to here as the products of the reaction.
In this case, we are asked to obtain the enthalpy change of the reaction. This tells us the heat that could have been absorbed or evolved in the reaction. We have to at this point know that the enthalpy change of the reaction gotten from;
Sum of enthalpy of the products - Sum of enthalpy of the reactants
ΔH = [(-484.5)] - [(-393.5) + (-74.8)]
ΔH = (-484.5) + 468.3
ΔH = -16.2 kJ/mol
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The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.
BALANCING EQUATION:
- Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.
- According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl
- Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:
4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl
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Answer: Strong (b)
Explanation:
INFRARED ACTIVE BONDS
Not all covalent bonds display bands in the IR spectrum. Only polar bonds do so. These are referred to as IR active.
The intensity of the bands depends on the magnitude of the dipole moment associated with the bond in question:
Strongly polar bonds such as carbonyl groups (C=0) produce strong bands.
