What happens when a catalyst is added to a chemical reaction that is already in progress?
1 answer:
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I have attached an image of the IR spectrum required to answer this question.
Looking at the IR, we can look for any clear major stretches that stand out. Immediately, looking at the spectrum, we see an intense stretch at around 1700 cm⁻¹. A stretch at this frequency is due to the C=O stretch of a carbonyl. Therefore, we know our answer must contain a carbonyl, so it could still be a ketone, aldehyde, carboxylic, ester, acid chloride or amide. However, if we look in the 3000 range of the spectrum, we see some unique pair of peaks at 2900 and 2700. These two peaks are characteristic of the sp² C-H stretch of the aldehyde.
Therefore, we can already conclude that this spectrum is due to an aldehyde based on the carbonyl stretch and the accompanying sp² C-H stretch.
Looking at the IR, we can look for any clear major stretches that stand out. Immediately, looking at the spectrum, we see an intense stretch at around 1700 cm⁻¹. A stretch at this frequency is due to the C=O stretch of a carbonyl. Therefore, we know our answer must contain a carbonyl, so it could still be a ketone, aldehyde, carboxylic, ester, acid chloride or amide. However, if we look in the 3000 range of the spectrum, we see some unique pair of peaks at 2900 and 2700. These two peaks are characteristic of the sp² C-H stretch of the aldehyde.
Therefore, we can already conclude that this spectrum is due to an aldehyde based on the carbonyl stretch and the accompanying sp² C-H stretch.
Answer:
Explanation:
The unbalanced nuclear equation is
It is convenient to replace the question by an atomic symbol, , where <em>x </em>= the atomic number, <em>y</em> = the mass number, and Z = the symbol of the element.
Then your equation becomes
The main point to remember in balancing nuclear equations is that the <em>sums of the superscripts and of the subscripts</em> must be the same on each side of the equation.
Then
93 – 1 = <em>x</em>, so <em>x</em> = 92
232 + 0 = <em>y</em>, so <em>y</em> = 232
Element 92 is uranium, so the nuclear equation becomes