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3 years ago

What happens when a catalyst is added to a chemical reaction that is already in progress?

Chemistry

1 answer:

Elanso [62]3 years ago

3 0

Explanation:

when the catalyst is added the reaction with the lower activation energy occur

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Explain why chlorine has a relative mass of 35.5?

Sedaia [141]

Answer: because of isotopes

relative atomic mass =(75/100 × 35) + (25/100 × 37) = 35.5

isotopes of any element behave the same chemically because neutrons do not have any charge

Explanation:

plz mark brainliest if helps

4 0

3 years ago

Please explain how to find each answer solution.

svp [43]

Explanation:

1) Based on the octet rule, iodine form an I⁻ ion.

Therefore,

Option E is correct ✔

2) The electronic configuration of the sulfide ion (S²⁻) is :

₁₆S = 1s² 2s² 2p⁶ 3s² 3p⁴ or [Ne] 3s² 3p⁴

₁₈S²⁻ = 1s² 2s² 2p⁶ 3s² 3p⁶ or [Ne] 3s² 3p⁶

Therefore,

Option E is correct ✔

3) valence shell electron of

Halogens = 7

Alkali metal = 1

Alkaline earth metal = 2

Therefore,

Option D is correct ✔

4) Group 2 element lose two electron in order to achieve Noble gas configuration.

And here Group 2 element is Sr

Therefore,

Option B is correct ✔

5) Group 13 element lose three electron in order to achieve Noble gas configuration.

And here Group 13 element is Al

Therefore,

Option B is correct ✔

6) For a given arrangements of ions, the lattice energy increases as ionic radius decreases and as ionic charge increases.

Therefore,

Option A is correct ✔

7 0

3 years ago

Determine the oh of a solution that is 0.220 m in hco3

ICE Princess25 [194]

Answer : The hydroxide ion concentration of a solution is, $5\times 10^{-14}$

Explanation :

As we know that $HCO_3^-$ dissociates in water to give hydrogen ion $(H^+)$ and carbonate ion $(CO_3^{2-})$ .

As, 1 mole of $HCO_3^-$ dissociates to give 1 mole of hydrogen ion $(H^+)$

Or, 1 M of $HCO_3^-$ dissociates to give 1 M of hydrogen ion $(H^+)$

So, 0.200 M of $HCO_3^-$ dissociates to give 0.200 M of hydrogen ion $(H^+)$

Now we have to calculate the hydroxide ion concentration.

As we know that:

$[H^+][OH^-]=1\times 10^{-14}$

$0.200\times [OH^-]=1\times 10^{-14}$

$[OH^-]=5\times 10^{-14}$

Therefore, the hydroxide ion concentration of a solution is, $5\times 10^{-14}$

6 0

4 years ago

How does the temperature and pressure change inside the earth, moving downward from the crust to the core?

Rus_ich [418]

B. Both temperature and pressure increase

8 0

3 years ago

Read 2 more answers

Draw the curved arrow mechanism for the addition of HCN in water with NaOH to 3,4-dimethylcyclopentan-1-one to give the correspo

Crank

Answer:

See picture and explanation below

Explanation:

In the attached picture you have the answer for this.

In the first step, we have an acid base reaction between HCN and NaOH. When this happens, its formed the following:

HCN + NaOH --------> CN⁻ + H₂O + Na⁺

As a second step, The CN⁻ attacks the carbonile group in the cyclopentane. This causes to open the double bond, and then, the Cyano enters the molecule.

The final step is another acid base reaction, where the oxygen substracts a hydrogen atom of the water in the medium, and then, the alcohol group is formed. With this step, the cyanohydrin is finally formed. See the mechanism below in the picture.

Hope this helps

6 0

3 years ago