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madreJ [45]
3 years ago
9

Juggles the clown stands on one end of a teeter-totter at rest on the ground. Bangles the clown jumps off a platform 2.4 m above

the ground and lands on the other end of the teeter-totter, launching Juggles into the air. Juggles rises to a height of 3.6 m above the ground, at which point he has the same amount of gravitational potential energy as Bangles had before he jumped, assuming both potential energies are measured using the ground as the reference level. Bangles' mass is 80 kg. What is Juggles' mass?
Physics
1 answer:
tester [92]3 years ago
5 0

Answer:

mj = 53.3kg

Explanation:

Since both gravitational energies are the same:

Eb = Ej   =>   mb*g*hb = mj*g*hj

Solving for mj:

mj = mb*hb/hj = 80*2.4/3.6

mj = 53.3kg

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A cannon fires a 40.5kg shell toward a target and the shell moves with a velocity of 120 m/s. Calculate the shells momentum
kvv77 [185]

Answer:

4860 kg m/s

Explanation:

P = mv

P = 40.5 x 120

P = 4860 kg m/s

8 0
2 years ago
A bird carrying a fish (5kg) drops it from 107 meters in the air how fast does the fish hit the ground
notka56 [123]

Answer:

The velocity of the fish hitting the ground is , v = 45.795 m/s        

Explanation:

Given data,

The mass of the fish, m = 5 kg

The height of the bird from the surface, h = 107 m

Using the III equation of motion,

                          v² = u² + 2gs

                          <em> v = √(u² + 2gs)</em>

Substituting the values,

                           v = √(0² + 2 x 9.8 x 107)  

                              = 45.795 m/s

Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s        

4 0
3 years ago
If a car moving down this road rounds this curve and changes its direction to the right, is this an example of speed, velocity,
mars1129 [50]

Answer: velocity

Explanation: it's the rate of change of the objects position/ consistent change

4 0
3 years ago
Read 2 more answers
The unit for energy is the​
nikitadnepr [17]

Explanation:

Joule (J) is the MKS unit of energy, equal to the force of one Newton acting through one meter.

4 0
4 years ago
The four tires of an automobile are inflated to a gauge pressure of 2.2 105 Pa. Each tire has an area of 0.023 m2 in contact wit
Stels [109]

Answer:

Force, F = 20240 N

Explanation:

It is given that,

Pressure exerted by the four tires of an automobile, P=2.2\times 10^5\ Pa

Area of each tire, A=0.023\ m^2

Area of 4 tires,  A=0.092\ m^2

We know that the pressure exerted by an object is equal to the force per unit area. Its formula is given by :

P=\dfrac{F}{A}

F=P\times A

F=2.2\times 10^5\times 0.092

F = 20240 N

So, the weight of the automobile is 20240 N. Hence, this is the required solution.

7 0
4 years ago
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