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madreJ [45]
3 years ago
9

Juggles the clown stands on one end of a teeter-totter at rest on the ground. Bangles the clown jumps off a platform 2.4 m above

the ground and lands on the other end of the teeter-totter, launching Juggles into the air. Juggles rises to a height of 3.6 m above the ground, at which point he has the same amount of gravitational potential energy as Bangles had before he jumped, assuming both potential energies are measured using the ground as the reference level. Bangles' mass is 80 kg. What is Juggles' mass?
Physics
1 answer:
tester [92]3 years ago
5 0

Answer:

mj = 53.3kg

Explanation:

Since both gravitational energies are the same:

Eb = Ej   =>   mb*g*hb = mj*g*hj

Solving for mj:

mj = mb*hb/hj = 80*2.4/3.6

mj = 53.3kg

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A worker pushed a 33 kg block 6.1 m along a level floor at constant speed with a force directed 23° below the horizontal. if the
jenyasd209 [6]
The work done occurs only in the direction the block was moved - horizontally. Work is given by:

W = F(h) * d

Where F(h) is the force applied in that direction (horizontal) and d is the distance in that direction. In this case, F(h) is the horizontal component of the applied force, F(app). However, the question doesn't give us F(app), so we need to find it some other way.

Since the block is moving at a constant speed, we know the horizontal forces must be balanced so that the net force is 0. This means that F(h) must be exactly balanced by the friction force, f. We can express F(h) as a function of F(app):

F(h) = F(app)cos(23)

Friction is a little trickier - since the block is being PUSHED into the ground a bit by the vertical component of the applied force, F(v), the normal force, N, is actually a bit more than mg:

N = mg + F(v) = mg + F(app)sin(23)

Now we can get down to business and solve for F(app) - as mentioned above:

F(h) = f
F(h) = uN
F(h) = u * (mg + F(v))
F(app)cos(23) = 0.20 * (33 * 9.8 + F(app)sin(23))
F(app) = 76.8

Now that we have F(app), we can find the exact value of F(h):

F(h) = F(app)cos(23)
F(h) = 76.8cos(23)
F(h) = 70.7

And now that we have F(h), we can find W:
W = F(h) * d
W = 70.7 * 6.1
W = 431.3

Therefore, the work done by the worker's force is 431.3 J. This also represents the increase in thermal energy of the block-floor system.
3 0
3 years ago
Projectile Motion—A tennis ball is thrown out a window 28 m above the ground at an initial velocity of 15.0 m/s and 20.0° below
NNADVOKAT [17]

Answer:

The distance will be x = 41.7 [m]

Explanation:

We must first find the components in the x & y axes of the initial velocity.

(v_{o})_{x} = 15*cos(20)= 14.09[m/s]\\(v_{o})_{y} = 15*sin(20)= 5.13[m/s]

The acceleration is the gravity acceleration therefore.

g = 9.81 [m/s^2]

Now we can calculate how long it takes to fall.

y=(v_{o})_{y}*t-0.5*g*t^2\\-28 = 5.13*t-0.5*9.81*t^2\\-28=-4.905*t^2+5.13*t\\4.905*t^2-5.13*t=28\\t = 2.96[s]

With this time we can find the horizontal distance that runs the projectile.

x=(v_{o})_{x}*t\\x=14.09*2.96\\x=41.7[m]

5 0
2 years ago
1. What affects a material's resistance?
Ghella [55]

Answer:

A. Thickness and temperature

Explanation:

3 0
3 years ago
A bullet with a mass of 0.020 kg collides with a 2.5 kg wooden block at
kondaur [170]

Answer:

151.2 m/s

Explanation:

m1 = 0.020 kg

m2 = 2.5 kg

vf = 1.2 m/s

m1v1 +m2v2 = (m1 +m2)vf

0.020v1 + 0 = (0.020 +2.5)(1.2)

---> 151.2 m/s

5 0
3 years ago
In a fusion reactor, the high temperature of the order of 108 k is required in order that what condition is met?
laila [671]
In order for a fusion reactor to function well, one of the important conditions to be met is a high temperature at 108 million Kelvin. This is six times hotter than the temperature of the sun's core. At this temperature, the element hydrogen's state is a plasma, not a gas, where the atoms are stripped of electrons and thus can move freely. This is an ideal condition to enable the reactor to function where it enables the hydrogen atoms to gather enough energy for the reaction which will occur in the later stages of the process. <span />
4 0
3 years ago
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