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grin007 [14]
3 years ago
14

You are given a solution of hcooh (formic acid) with an approximate concentration of 0.20 m and you will titrate this with a 0.1

105 m naoh. you add 20.00 ml of hcooh to the beaker before titrating, and it requires 35.43 ml of naoh to reach the end point. what is the concentration of the hcooh solution?
Chemistry
2 answers:
Kruka [31]3 years ago
7 0

Answer: 0.1958 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

HCOOH+NaOH\rightarrow HCOONa+H_2O

According to the neutralization law,:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HCOOH solution = ?

V_1 = volume of HCOOH solution = 20.00 ml

M_2 = molarity of NaOH solution = 0.1105 M

V_2 = volume of NaOH solution = 35.43 ml

n_1 = valency of HCOOH = 1

n_2 = valency of NaOH = 1

1\times M_1\times 20.00=1\times 0.1105\times 35.43

M_1=0.1958

Therefore, the concentration of the HCOOH is 0.1958 M

balu736 [363]3 years ago
6 0
V(NaOH)*M(NaOH)=V(HCOOH)M(HCOOH)
35.43ml*0.1150m=20.00ml*M(HCOOH)
M(HCOOH)=0.2037m
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Hello there!

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