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siniylev [52]
3 years ago
14

Las fórmulas actuales de los compuestos propuestos por Dalton

Chemistry
1 answer:
KonstantinChe [14]3 years ago
6 0

Answer:

La teoría atómica de Dalton fue el primer intento completo para describir toda la materia en términos de los átomos y sus propiedades.

Dalton basó su teoría en la ley de la conservación de la masa y la ley de la composición constante.

La primera parte de su teoría establece que toda la materia está hecha de átomos, que son indivisibles.

La segunda parte de su teoría establece que todos los átomos de un elemento dado son idénticos en masa y en propiedades.

La tercera parte de su teoría establece que los compuestos son combinaciones de dos o más tipos diferentes de átomos.

La cuarta parte de su teoría establece que una reacción química es un reordenamiento de átomos.

Partes de su teoría tuvieron que ser modificadas con base en el descubrimiento de las partículas subatómicas y los isótopos.

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Using the HH eq. calculate the amounts (masses) of sodium phosphate monobasic monohydrate (NaH2PO4 H2O) and sodium phosphate dib
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An acidic solution will turn litmus paper Question 2 options:
Sloan [31]

Answer:

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Explanation:

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Read 2 more answers
Geraniol, C10H17OH, is an rose-scented alcohol commonly used in perfumes. How many grams of geraniol should be added to 600. mL
Maksim231197 [3]

Answer:

215.12 g

Explanation:

The change in the bolling temperature is a collateral property called ebullioscopy. The elevation on temperature occurs because there'll be a solute in the pure compound, and that solute(generally non-volatile) has a different boiling point, so the total bolling pint should increase.

To calculate the elevation in the temperature, we must use the Raoult equation:

ΔT = KbxWxi

Where <em>ΔT</em> is the variation of the temperature of boiling point, <em>Kb</em> is the

ebullioscopy constant, <em>W</em> is the molarity, and <em>i</em> the Vant' Hoff factor, which for molecules is also equal to 1, because they don't form ions. So:

82.00 - 78.40 = 1.22xW

W = 3.60/1.22

W = 2.9508

The molarity can also be calculated by:

W = \frac{m1}{M1xm2}

Where <em>m1</em> is the mass of the solute (in grames), <em>M1</em> is the molar mass of the solute, and <em>m2</em> is the mass of the solvent (in kg).

The density of ethanol is 0.789 g/cm³, and 1 mL = 1 cm³, so 600.00 mL = 600.00 cm³ :

0.789 = m2/600

m2 = 473.4 g = 0.4734 kg

The molar mass of geraniol is:

C: 12 g/mol x 10 = 120 g/mol

H: 1 g/mol x 18 = 18 g/mol

O: 16 g/mol x 1 = 16 g/mol

M1 = 154 g/mol

Then:

2.9508 = \frac{m1}{154x0.4734}

m1 = 215.12 g of geraniol.

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