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siniylev [52]
3 years ago
14

Las fórmulas actuales de los compuestos propuestos por Dalton

Chemistry
1 answer:
KonstantinChe [14]3 years ago
6 0

Answer:

La teoría atómica de Dalton fue el primer intento completo para describir toda la materia en términos de los átomos y sus propiedades.

Dalton basó su teoría en la ley de la conservación de la masa y la ley de la composición constante.

La primera parte de su teoría establece que toda la materia está hecha de átomos, que son indivisibles.

La segunda parte de su teoría establece que todos los átomos de un elemento dado son idénticos en masa y en propiedades.

La tercera parte de su teoría establece que los compuestos son combinaciones de dos o más tipos diferentes de átomos.

La cuarta parte de su teoría establece que una reacción química es un reordenamiento de átomos.

Partes de su teoría tuvieron que ser modificadas con base en el descubrimiento de las partículas subatómicas y los isótopos.

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For the reaction N2(g) + 3H2(g) 2NH3(g), what will happen if hydrogen gas was removed from the reaction mixture? There will be a
Hoochie [10]
This uses something called <span>Le Chatelier's principle. It states essentially that any stress put upon a system will be corrected.

In more simple terms, it means that in an equilibrium, such as the equation N2(g) + 3H2(g) <=> 2NH3(g), removing a reactant will cause the system to create more of said reactant to compensate for its loss, or adding excess reactant will cause the system to remove some of the added reactant. For future reference, the same principle applies to products in an equilibrium as well. 

In this case, hydrogen gas is a reactant, and hydrogen is being removed. According to </span><span>Le Chatelier's principle, the system will shift to create more hydrogen gas. In essence, it will shift in the direction of the hydrogen gas, so there will be a shift toward the reactants.

To clear something up, Keq will not change, as it is a constant value with constant conditions (such as temperature, pressure, etc.).</span>
7 0
3 years ago
Barium phosphide Ba3P2 BaP Ba3PO4
Novosadov [1.4K]

Answer:

It A(Ba3P2)

Explanation:

I took the test

6 0
3 years ago
The isotopic mass of ²¹⁰₈₆Rn is 209.989669amu. When this nuclide decays by electron capture, it emits 2.368 MeV. What is the iso
zaharov [31]

Starting from the radon mass, add the mass of the electron, and subtract the mass attributable to the gamma radiation <u>(931 Mev = 1 amu).</u>

<u></u>

<h3>What is gamma radiation?</h3>

Gamma radiation (gamma rays) refers to the part of the electromagnetic spectrum with the most energy and shortest wavelength. Astrophysicists define gamma radiation as any radiation with an energy above 100 keV. Physicists define gamma radiation as high-energy photons released by nuclear decay.

Using the broader definition of gamma radiation, gamma rays are released by sources including gamma decay, lightning, solar flares, matter-antimatter annihilation, the interaction between cosmic rays and matter, and many astronomical sources. Gamma radiation was discovered by Paul Villard in 1900.

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Learn more about gamma radiation

brainly.com/question/20799041

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5 0
1 year ago
If a substance has a mass of 12.50 g and takes up 3.4 mL of space, what is the density?
miskamm [114]

Answer:

The answer is

<h2>3.68 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass of substance = 12.50 g

volume = 3.4 mL

The density of the substance is

density =  \frac{12.50}{3.4}  \\  = 3.676470588...

We have the final answer as

<h3>3.68 g/mL</h3>

Hope this helps you

7 0
3 years ago
Calculate the moles and grams of solute in 2.0 L of 0.30M Na SO..
Ostrovityanka [42]

Answer:

Number of moles of solute = 0.6 mole

Mass =13.8 g

Explanation:

Given data:

Number of moles of sodium = ?

Volume = 2.0 L

Molarity = 0.30 M

Mass in gram of sodium= ?

Solution:

<em>Number of moles:</em>

Molarity = number of moles of solute / volume in litter

Number of moles of solute = Molarity × volume in litter

Number of moles of solute = 0.30 M × 2.0 L

Number of moles of solute = 0.6 mole

<em>Mass in gram:</em>

Mass = Number of moles × molar mass

Mass = 0.6 mole× 23 g/mol

Mass =13.8 g

3 0
3 years ago
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