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kondor19780726 [428]
3 years ago
13

When copper (II) chloride reacts with sodium nitrate, copper (II) nitrate and sodium chloride are formed.

Chemistry
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

How many grams of copper (II) nitrate is formed

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Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and wil
emmainna [20.7K]

Answer:

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

<em>Moles H2SO4:</em>

0.650L * (0.430mol /L) = 0.2795moles H2SO4

<em>Moles KOH:</em>

0.600L * (0.240mol / L) = 0.144 moles KOH

Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

In 0.650L + 0.600L = 1.25L:

Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

<h3>0.166M</h3>
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What is the temperature difference if 300 cal are used to warm water
PIT_PIT [208]

Answer:

<u>The temperature difference is</u> \frac{300}{m} Kkg^{-1}

Explanation:

The formula that is to used is :

ΔQ=msΔT

<em>where ,</em>

  • <em>ΔQ is the heat supplied in calories = 300cal</em>
  • <em>m is the mass of water taken = m (assumed)</em>
  • <em>ΔT is the change in temperature</em>
  • <em>s is the specific heat of water = 1calK^{-1}Kg^{-1}</em>

ΔT :

\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}

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