When copper (II) chloride reacts with sodium nitrate, copper (II) nitrate and sodium chloride are formed.
1 answer:
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Explanation:
Formula to calculate how many particles are left is as follows.
N =
where, = number of initial particles
l = number of half lives
As it is given that number of initial particles is and number of half-lives is 3.
Hence, putting the given values into the above equation as follows.
N =
=
=
or,
Thus, we can conclude that particles of radioactive nuclei remain in the given sample.
In five hours we've gone through 5 half lives so the answer is:
particles