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sp2606 [1]
3 years ago
5

If the neutral solution was boiled to dryness, what would be the formula of the resulting salt.

Chemistry
1 answer:
mash [69]3 years ago
7 0

Answer:

Forumula

XOH + HY = XY + H2O

Explanation:

Salt formed from: Salt Solution

Strong acid + Strong base Neutral

Strong acid + Weak base Acidic

Weak acid + Strong base Basic

Neutral solution example

NaCl = Sodium chloride

HCl = H+ and Cl-

NaOH = Na+ and OH-

OH- = Strong Base

H+ = Strong Acid

Sodium chloride, formed from neutralization of HCl by NaOH.

NaOH + HCl = NaCl + H2O

NaCl in water is not acidic or basic, since it's ions cannot hydrolyze.

So formula would be XOH + YH = XY + H2O

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Hitman42 [59]

Answer:

seven electrons

Explanation:

Chlorine is present in group seventeen of periodic table. It is halogen element. All halogens have seven electrons in outer most valance shell.

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Abbreviated electronic configuration:

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Properties of chlorine:

1. it is greenish-yellow irritating gas.

2. its melting point is 172.2 K

3. its boiling point is 238.6 K

4. it is disinfectant and can kill the bacteria.

5. it is also used in manufacturing of paper, paints and textile industries.

5 0
3 years ago
Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much sulfur dioxide
taurus [48]
1) Balanced chemical equation:

2SO2 (g) +  O2 (g) -> 2SO3 (l)

2) Molar ratios

2 mol SO2 : 1 mol O2 : 2 mol SO3

3) Convert 6.00 g O2 to moles

number of moles = mass in grams / molar mass

number of moles = 6.00 g / 32 g/mol = 0.1875 mol O2.

4) Use proportions with the molar ratios

=> 2 moles SO2 / 1 mol O2 = x / 0.1875 mol O2

=> x = 0.1875 mol O2 * 2 mol SO2 / 1 mol O2 = 0.375 mol SO2.

5) Convert 0.375 mol SO2 to grams

mass in grams = number of moles * molar mass

molar mass SO2 = 32 g/mol + 2*16 g/mol = 64 g/mol

=> mass SO2 = 0.375 mol * 64 g / mol = 24.0 g

Answer: 24.0 g of SO2 are needed to react completely with 6.00 g O2.
7 0
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