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sp2606 [1]
3 years ago
5

If the neutral solution was boiled to dryness, what would be the formula of the resulting salt.

Chemistry
1 answer:
mash [69]3 years ago
7 0

Answer:

Forumula

XOH + HY = XY + H2O

Explanation:

Salt formed from: Salt Solution

Strong acid + Strong base Neutral

Strong acid + Weak base Acidic

Weak acid + Strong base Basic

Neutral solution example

NaCl = Sodium chloride

HCl = H+ and Cl-

NaOH = Na+ and OH-

OH- = Strong Base

H+ = Strong Acid

Sodium chloride, formed from neutralization of HCl by NaOH.

NaOH + HCl = NaCl + H2O

NaCl in water is not acidic or basic, since it's ions cannot hydrolyze.

So formula would be XOH + YH = XY + H2O

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Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

  • x is the oxidation number

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#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

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