Answer: The question has some details missing. here is the complete question ; An analytical chemist is titrating 88.4 mL of a 0.2700 M solution of ammonia (NH3 with a 0.4300 M solution of HNO3. The pK, of ammonia is 4.74 Calculate the pH of the base solution after the chemist has added 66.3 mL of the HNO3 solution to it . Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution
Explanation:
Given ;
- number of moles of base = 88.4 x 0.2700 = 23.868
- number of moles of acid = 0.4300 x 66.3 = 28.509
- This was after the equivalence point, as such net moles of acid = 28.509 - 23.868 = 4.641mol
- total volume of solution = 88.4 + 66.3 = 154.7mL
- Concentration of Acid = moles/volume = 4.641/154.7 = 0.03M
- From pH = -log[H^+] = -Log[0.03]
Answer:
HNO3 is a strong acid
HCl is also a strong acid
NaCl is a salt so it is neither a strong acid nor a strong base
Ca(OH)3 is a strong base
Explanation:
A<em>nswer:</em>
The possible branched chain structure of alcohols with chemical formula C5H12O are following.
- 3-methylbutan-2-ol
- 3-methylbutan-1-ol
- 2,2-dimethylpropan-1-ol
- pentan-3-ol
- 2-methylbutan-1-ol
- 2-methylbutan-2-ol
Structure:
Please see attachment
Answer:
Technology helps us in many ways.
Explanation:
We can now research the world even more effectively and at a higher level of sophistication thanks to technological advancements. Telescopes, on the other hand, enable us to peer into the far corners of the universe and detect very large objects such as stars. Electron microscope enable us to see smaller objects such as cells and organisms.
Answer:
its ability to lose electron
