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Sav [38]
2 years ago
6

for a neutralization reaction, would you expect the magnitude of q to increase, decrease, or stay the same if the concentration

of only the acid were doubled? why?
Chemistry
1 answer:
ikadub [295]2 years ago
4 0

For a neutralization reaction, the value of q(heat of neutralization) is doubled when the concentration of only the acid is doubled.

A neutralization reaction is a reaction in which an acid reacts with a base to yield salt and water. Ionically, a neutralization reaction goes as follows; H^+(aq) + OH^-(aq) ------> H20(l).

The heat of neutralization (Q) of the system depends on the concentration of the solutions. Since Q is dependent on concentration, if the concentration of any of the reactants is doubled, more heat is evolved hence Q is doubled.

Learn more: brainly.com/question/10323185

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According to the following reaction, how many moles of chlorine gas are necessary to form 0.739 moles carbon tetrachloride? carb
Ilia_Sergeevich [38]

Answer:

2.956 moles chlorine gas will be produced

Explanation:

Step 1: data given

Number of moles carbon tetrachloride (CCl4) = 0.739 moles

carbon disulfide (s) = CS2(s)

chlorine (g) = Cl2(g)

carbon tetrachloride (l) = CCl4(l)

sulfur dichloride (s) = SCl2 (s)

Step 2: The balanced equation

CS2(s) + 4Cl2(g) → CCl4(l) +2SCl2

Step 3: Calculate moles chlorine gas

For 1 moles Cs2 we need 4 moles Cl2 to produce 1 mol CCl4 and 2 moles SCl2

For 0.739 moles CCl4 we need 4*0.739 = 2.956 moles Cl2

2.956 moles of chlorine gas will be produced

4 0
3 years ago
What occurs when zero visibility is caused by heavy snowfall combined strong updrafts and downdrafts
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A whiteout occurs when strong updrafts and downdrafts combine 
4 0
3 years ago
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CHEM PLZ HELP, Which thermochemical equation represents the most exothermic reaction?
uysha [10]

Answer:

The answer is option 3, C5H12 + 8O2 → 5CO2 + 6H2O.

Explanation:

In an exothermic reaction, the energy change(ΔH) will always be a negative value.

For endothermic reaction, the energy change's value is positive.

In the options above, option 1 and 2 are endothermic reaction.

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3 years ago
Which is true about the total mechanical energy in a closed system?
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Determine the formula weights of each of the following compounds.Part A) Nitrous oxide, N2O, known as laughing gas and used as a
densk [106]

Answer:

See explanation

Explanation:

a) Nitrous oxide (N2O) has a molar mass of 44.014 amu. It has 2 nitrogen atoms each with a mass of 14.007 amu and 1 oxygen atom with a mass of 16.0 amu.

Percentage nitrogen = (2*14.007 amu/ 44.014 amu ) *100% = 63.6%

Percentage oxygen = (16 amu/44.014 amu) * 100% = 36.4 %

63.6% + 36.4% = 100%

b) Benzoic acid (C7H6O2) has a molar mass of 122.13 amu. It has 6 hydrogen atoms each with a mass of 1.01 amu; it has 7 carbon atoms each with a mass of 12.01amu and 2 oxygen atoms with a mass of 16.0 amu.

Percentage hydrogen = (6*1.01 amu / 122.13 amu)*100% = 4.96%

Percentage carbon = (7*12.01 amu/ 122.13 amu)*100% = 68.8%

Percentage oxygen = (2*16 amu/ 122.13 amu) *100% = 26.2%

c) Magnesium hydroxide (Mg(OH)2) has a molecular mass of 58.32 amu. It has 2 hydrogen atoms each with a mass of 1.01 amu; it has 1 magnesium atom with a mass of 24.3 amu and two oxygen atoms with a mass of 16.0 amu.

Percentage hydrogen = (2*1.01 amu/ 58.32 amu) *100% = 3.46 %

Percentage magnesium = (24.3 amu/58.32 amu)*100% = 41.7%

Percentage oxygen = (2*16 amu/58.32 amu)*100% = 54.9%

d) Urea CO(NH2)2 has a molecular mass of 60.064 amu. It has 2 Nitrogen atoms each with a mass of 14.007 amu, 4 hydrogen atoms each with a mass of 1.01 amu,1 carbon atom with a mass of 12.01 amu and 1 oxygen atom with a mass of 16.0 amu.

Percentage nitrogen = (2*14.007 amu/ 60.064amu)*100% = 46.6%

Percentage hydrogen = (4*1.01 amu/60.064amu)*100% = 6.72%

Percentage carbon = (12.01 amu/60.064amu)*100% = 20.0%

Percentage oxygen = (16 amu/60.064amu)*100% = 26.6%

e) Osopentyl acetate (C7H14O2) has a molecular mass of 130.2 amu. It has 14 hydrogen atoms each with a mass of 1.01 amu,7 carbon atoms each with a mass of 12.01 amu and 2 oxygen atom with a mass of 16.0 amu.

Percentage hydrogen = (14*1.01 amu/130.2 amu)*100% = 10.8%

Percentage carbon = (7*12.01 amu/130.2 amu)*100% = 64.6%

Percentage oxygen =(2*16 amu/130.2 amu)*100% = 24.6%

7 0
3 years ago
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