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Yanka [14]
3 years ago
5

4,600,000,000,000 in scientific notation

Chemistry
1 answer:
BabaBlast [244]3 years ago
6 0
4.6to the twelth power plus ten or something like that it has been a while since I have done the scientific notation but where ever you put in the number of zeros. is twelve
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Why does the colour of copper sulphate solution change when an iron nail is dipped in it?
sineoko [7]

Answer:

bcoz iron displaces copper and form the solution iron sulfide

Explanation:

when we dip iron nail in copper sulfate solution,then iron starts reacting with the solution and due to displacement reaction between them iron is stronger metal than copper so it displaces copper and form iron sulfide:

CuSO4+3Fe---->Fe3SO4+Cu

4 0
3 years ago
What differences do you notice when you heat up the brick and the iron at same temperature?
Tpy6a [65]

After heating the brick and the iron, it is observed that the brick heats up quicker and the brick releases energy quicker.

<h3>What is thermal energy?</h3>

Thermal energy (also called heat energy) is produced when a rise in temperature causes atoms and molecules to move faster and collide with each other.

The iron has more energy than the brick even though it is at the same temperature. That means that the iron must have more particles than the brick.

Iron and brick are both solids and have the same volume, so the difference in total energy must be due to atomic composition.

Learn more about thermal energy here:

brainly.com/question/14506133

#SPJ1

5 0
2 years ago
A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?
MariettaO [177]

On the basis of the given data:

Volume (V) is 37.5 L

Temperature (T) is 307 K

Pressure (P) is 1.25 atm

In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K

n = PV / RT

n = 1.25 atm × 37.5 L / 0.0821 Latm/mol/K × 307 K

n = 1.85 mol

3 0
3 years ago
For the reaction IO3–(aq) + 5 I–(aq) + 6 H+(aq) → 3 I2(aq) + 3 H2O(l) the rate of disappearance of I–(aq) at a particular time a
scoray [572]

Answer: The rate of appearance of I_2(aq) is 1.44\times 10^{-3}mol/Ls

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

IO_3^-(aq)+5I^-(aq)+6H^+(aq)\rightarrow 3I_2(aq)+3H_2O(l)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[I^-]}{5dt}=+\frac{d[I_2]}{3dt}

Given: -\frac{d[I^-]}{dt}] = 2.4\times 10^{-3}mol/Ls

+\frac{d[I_2]}{dt}=-\frac{3d[I^-]}{5dt}=-\frac{3}{5}\times 2.4\times 10^{-3}mol/Ls=1.44\times 10^{-3}mol/Ls

The rate of appearance of I_2(aq) is 1.44\times 10^{-3}mol/Ls

6 0
3 years ago
martha needs to determine the density of gasoline she has determined the mass to be 1250g and the volume to be 1500ml what is th
Dahasolnce [82]

We know that the equation for density is:

D=\frac{m}{V}

where D is the density, m is the mass in grams, and V is the volume.

Given two of the variables, we can then solve for density:

D=\frac{1250g}{1500mL}=\frac{0.833g}{mL}

Therefore, we now know that the density of the gasoline is 0.833g/mL.

6 0
3 years ago
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