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xenn [34]
3 years ago
10

Liam uses 2 quarts of yellow paint and adds 3 1/4 Jars of blue paint.Evan uses 1/2 quarts of yellow paint and adds 5 1/2 of red

paint.They end up with the same volume of paint.write an equation to show it.
Mathematics
1 answer:
EleoNora [17]3 years ago
7 0

Answer:

2 + (13/4)x = 1/2 + (11/2)y

Step-by-step explanation:

Let each jar of paint used by Liam be x

Let each jar of paint used by Evan be y.

Liam uses 2 quarts of yellow paints and adds 3 1/4 jars of blue paint. so we have

2 + 3 1/4x

= 2 + (13/4)x

Since Evan also uses 1/2 quarts of yellow paints and add 5 1/2 jar of red paint, we have

1/2 + 5 1/2y

= 1/2 + (11/2)y

Since they end up with the same volume of paint, we have

2 + (13/4)x = 1/2 + (11/2)y

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Questions:
My name is Ann [436]

The  solution to the expressions given are;

9 -9t/ 12 - 5t

a. 20/ 169

b. -170/ 169

c.  386/ 169

d.  -10/ 169

<h3>How to solve the expressions</h3>

Given:

\frac{9 - 19t}{12 - 5t}

We can see that both variables in the numerator and denominator have no common factor, thus cannot be factorized further

a. \frac{203}{169} - \frac{183}{169}

First, let's find the lowest common multiple

LCM = 169

= \frac{203 - 183}{169}

= \frac{20}{169}

= 20/ 169

b. \frac{13}{119} - \frac{183}{119}

The lowest common multiple is 119

= \frac{13 - 183}{119}

substract the numerator

= - 170/ 119

c. \frac{203}{169} - \frac{183}{169}

The lowest common multiple is 169

= \frac{203 + 183}{169}

= 386/ 169

d. \frac{9}{169}- \frac{19}{169}

The lowest common multiple is 169

= \frac{9 - 19}{169}

= - 10/ 169

Thus, we have the solutions to be 9 -9t/ 12 - 5t, 20/ 169, -170/ 169, 386/ 169, -10/ 169 respectively.

Learn more about LCM here:

brainly.com/question/12732917

#SPJ1

7 0
2 years ago
Brainliest if correct
harkovskaia [24]

Answer:

3/8 & 4/8

Step-by-step explanation:

1/2 - 1/8 = 4/8 - 1/8 = 3/8

x - 1/8 = 3/8

x = 4/8    

6 0
3 years ago
Find the slope: x + 7y = 21​
Aleksandr [31]

Answer:  1/7

Step-by-step explanation:

solve for y

7 0
3 years ago
Solve for x and y:<br> 3/x -1/y =13/10<br> 1/x + 2/y =9/10
harkovskaia [24]

Answer:

  (x, y) = (2, 5)

Step-by-step explanation:

I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...

  3x' -y' = 13/10

  x' +2y' = 9/10

Adding twice the first equation to the second, we get ...

  2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)

  7x' = 35/10 . . . . . . simplify

  x' = 5/10 = 1/2 . . . . divide by 7

Using the first equation to find y', we have ...

  y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5

So, the solution is ...

  x = 1/x' = 1/(1/2) = 2

  y = 1/y' = 1/(1/5) = 5

  (x, y) = (2, 5)

_____

The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.

3 0
3 years ago
The vertex form of the function <br> y=x^2+8x+29
stira [4]

Answer:

y = (x+4)^2 +13

Step-by-step explanation:

y=x^2+8x+29

To complete the square take  the coefficient of the x term

8

Divide by 2

8/2 =4

Then square it

4^2 =16

y=x^2+8x+16+13

 = (x^2+8x+16)  +13

 = (x+4)^2 +13

5 0
3 years ago
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