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Answer : The maximum amount of nickel(II) cyanide is 
Explanation :
The solubility equilibrium reaction will be:

Initial conc. 0.220 0
At eqm. (0.220+s) 2s
The expression for solubility constant for this reaction will be,
![K_{sp}=[Ni^{2+}][CN^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BNi%5E%7B2%2B%7D%5D%5BCN%5E-%5D%5E2)
Now put all the given values in this expression, we get:


Therefore, the maximum amount of nickel(II) cyanide is 
If we convert the ounces to grams, there are approximately 283.495 grams of plant fertiliser
If nitrogen has 15% of this, all we have to do is divide this number by 100 to get the mass of 1% and multiply it by 15.
In the end, we end up with the mass of 42.5243 g
Hope I helped! xx