The answer can be explained when you burn something cleanly (with a very hot item) or not. With a candle lots of Carbon dioxide is producted but when using a bunson burner hardly any CO2 is produced.
A pi bond is a bond formed by the overlap of orbitals in a side-by-side fashion with the electron density concentrated above and below the plane of the nuclei of the bonding atoms. ... Three sigma bonds are formed from each carbon atom for a total of six sigma bonds total in the molecule.
Answer:
(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.
Explanation:
According to the Kelvin–Planck statement of the second law of thermodynamics ,it is not possible to construct a device which operates in cycle and does not produce effect on the environment than the production of work.
We know that
Coefficient of performance is the ratio of desired effect to the work input in a cycle.
Given all option is correct but most appropriate option is a.
So the option a is correct
(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.
By start heating the water so,
1- the physical changes to the water will begin by going through different states of matter such as solid, liquid and gas vapor.
2- Water is a compound, not an element (H2o).
3- It will change according to the temperature change also:
a- At zero C° it is at a freezing temperature.
b- when it starts to be heated from 0C° to 100 c°, it starts to change from freezing to the liquid state.
c- At 100C° the water starts to change from liquid to vapor state until it disappears.
