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tia_tia [17]
3 years ago
9

An example for curvilinear motion.

Physics
1 answer:
Shkiper50 [21]3 years ago
5 0

Ball thrown into the air at an angle.

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How many electrons are contained on the negatively-charged side of a capacitor when it is fullycharged if it is connected to a 1
AVprozaik [17]

Answer:

Explanation:

Capacitance of the capacitor

C = ε₀ A / d

(8.85 x 10⁻¹² x .25² x 10⁻⁴) / 1 x 10⁻³

C = .553125 x 10⁻¹³ F

Charge = capacitance x volt

= .553125 x 10⁻¹³ x 1.5

= .8296875 x 10⁻¹³ C

no of electrons

= charge / charge on one electron

= .8296875 10⁻¹³/ 1.6 x 10⁻¹⁹

= 5.2 x 10^5

3 0
4 years ago
Read 2 more answers
A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 60 m/s and 80 m/s, respectivel
DerKrebs [107]

This question involves the concepts of projectile motion and launch speed.

(a) The initial launch speed of the projectile is "100 m/s".

(b) The launch angle of the projectile is "53.13°".

<h3>(a) LAUNCH SPEED</h3>

A projectile motion is a motion that takes place on both x and y axes, simultaneously. In this motion the initial launch speed is given by the following formula:

v_o=\sqrt{v_{ox}^2+v_{oy}^2}

where,

  • v_o = initial launch speed = ?
  • v_{ox} = horizontal component of initial launch speed = 60 m/s
  • v_{oy} = vertical component of initial launch speed = 80 m/s

Therefore,

v_o = \sqrt{(60\ m/s)^2+(80\ m/s)^2}\\\\v_o = 100 m/s

<h3>(b) LAUNCH ANGLE</h3>

Launch angle is given by th following formula:

\theta = tan^{-1}(\frac{v_{oy}}{v_{ox}})=tan^{-1}(\frac{80\ m/s}{60\ m/s})\\\\\theta=53.13^o

Learn more about the projectile motion here:

brainly.com/question/11049671

6 0
3 years ago
Who wants to play Minecraft education edition with me the IP Address is 192.168.1.12
LekaFEV [45]

Answer:

Ok hold up

Explanation:

3 0
3 years ago
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Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field acting perpendicul
ANEK [815]

Answer:

4.14 cm.

Explanation:

Given,

For Coil 1

radius of coil, r₁ = 5.6 cm

Magnetic field, B₁ = 0.24 T

For Coil 2

radius of coil, r₂ = ?

Magnetic field, B₂ = 0.44 T

Using formula of maximum torque

\tau_{max}= NIAB

Since both the coil experience same maximum torques

now,

NIA_1B_1 = NIA_2B_2

A_1B_1 = A_2B_2

r_1^2 B_1 = r_2^2 B_2

5.6^2\times 0.24= r_2^2\times 0.44

r_2 = 4.14\ cm

Radius of the coil 2 is equal to 4.14 cm.

4 0
4 years ago
Compare these two waves
otez555 [7]

None of the choices in the picture is correct.

The blue wave has a higher pitch than the orange one, (because its waves are shorter so there are more of them in the same length of time).

AND the blue wave is also louder than the orange one, (because the amplitude of its waves is slightly greater).

4 0
3 years ago
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