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2 years ago

What unit is used to count atoms and molecules?

Physics

1 answer:

murzikaleks [220]2 years ago

7 0

the answer in my opinion would be A

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A train slows from 60m/s to 20m/s in 50s

Dovator [93]

Answer:

a = -4/5 m/s^2

Explanation:

Acceleration = change in velocity / time

change in velocity = final velocity - initial velocity

a = (20 m/s - 60 m/s) / 50 s

a = -40 m/s / 50 s

a = -4/5 m/s^2

hope this helps! <3

7 0

1 year ago

Read 2 more answers

A1.200 kg car is sliding down an icy

Triss [41]

Answer:

1585.67N

Explanation:

their are many student who can not get answer on time and step by step answer.so there are

a wats up group of experienced experts who helps you for free with step by step answer.just join this and get answer.

5 0

3 years ago

What is the equivalent resistance for a series circuit with three resistors : 5.0 ohms, 2.0 ohms, and 12.0 ohms

vesna_86 [32]

Answer:19ohms

Explanation:

equivalent resistance=5+2+12

equivalent resistance=19ohms

8 0

3 years ago

A sprinter starts from rest and runs with constant acceleration to a top speed of 12m/s in 4.0 seconds.

bagirrra123 [75]

Answer:

a = 3,0 m/s²

Explanation:

En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.

v= v₀ + a t

como el corredor parte del reposo si velocidad inicial es cero

v = at

a = v/t

calculemos

a = 12 /4,0

a = 3,0 m/s²

4 0

3 years ago

A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th

vladimir1956 [14]

Answer:

Force, $F=2.27\times 10^4\ N$

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

$F.d=\dfrac{1}{2}m(v^2-u^2)$

Finally, it stops, v = 0

$F.d=-\dfrac{1}{2}m(u^2)$

$F=\dfrac{-mu^2}{2d}$

$F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}$

F = -22713.92 N

$F=2.27\times 10^4\ N$

So, the magnitude of the force that stops the bullet is $2.27\times 10^4\ N$

7 0

2 years ago