Use the table to answer the question
2 answers:
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Answer : The concentration of is,
Explanation :
When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is and
is excess reagent.
First we have to calculate the moles of KSCN.
Moles of KSCN = Moles of = Moles of
=
Now we have to calculate the concentration of
Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L
Thus, the concentration of is,