I think it's 4 but I am not even 50% sure... But I think that is the answer..
Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
![Y = \dfrac{[L]}{k_d+[L]}](https://tex.z-dn.net/?f=Y%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7Bk_d%2B%5BL%5D%7D)
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
![0.25 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.25%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
![0.6 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.6%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
![0.95 = \dfrac{[L]}{400+[L]}](https://tex.z-dn.net/?f=0.95%20%3D%20%5Cdfrac%7B%5BL%5D%7D%7B400%2B%5BL%5D%7D)
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm
The answer is number 1 - energy is emitted
Energy is released when an atom in an excited state returns to the ground state.
Answer:
C) solid, liquid, gas
Explanation:
Which grouping shows a decrease in Intermolecular
Forces of Attraction?
A) gas, liquid, solid B) liquid, solid, gas
C) solid, liquid, gas D) solid, gas, liquid
the further the particles are from each other, the less the intermolecular attraction they are farthest in a gas, then a liquid, and closest in a solid
Answer: 1/12
1/4 divided by 3/1
KCF:Keep the first fraction, Change the sign to muplication, Flip the second fraction.
1/4* 31
1*1=1
4*3=12
1/12