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KIM [24]
3 years ago
13

4. What is the molarity of a solution that contains 65g of sodium nitrate in 750? ml of solution?

Chemistry
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

1.02 M

Explanation:

Solution contains 65g of sodium nitrate

Volume of solution = 750 ml

Now, Molar mass of sodium nitrate from online values = 84.9947 g/mol

Thus, it means 84.9947 g/mol of sodium nitrate dissolved in 1000 mL of water will be equal to 1 M molarity.

Thus;

Molarity of solution = (65/750) × (1000) × (1/84.9947) = 1.02 M

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Kipish [7]

1.05moles

Explanation:

Given parameters:

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Unknown:

Number of moles = ?

Solution:

The mole is the amount of substances that contains Avogadro's number of particles i.e 6.02 x 10²³

 To find the number of moles:

  number of moles = \frac{number of particles}{Avogadro's number}

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Learn more:

moles brainly.com/question/1841136

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A sample of 211 g of iron (III) bromide is reacted with
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FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

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\tt n=\dfrac{186}{78.0452}=2.38

Coefficient ratio from the equation FeBr₃ :  Na₂S = 2 : 3, so mol ratio :

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So  FeBr₃ as a limiting reactant(smaller ratio)

mol NaBr based on limiting reactant (FeBr₃) :

\tt \dfrac{6}{3}\times 0.714=1.428

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