Answer : The mass of copper deposit is, 1.98 grams
Explanation :
First we have to calculate the charge.
Formula used : ![Q=I\times t](https://tex.z-dn.net/?f=Q%3DI%5Ctimes%20t)
where,
Q = charge = ?
I = current = 10 A
t = time = 10 min = 600 sec (1 min = 60 sec)
Now put all the given values in this formula, we get
![Q=10A\times 600s=6000C](https://tex.z-dn.net/?f=Q%3D10A%5Ctimes%20600s%3D6000C)
Now we have to calculate the number of atoms deposited.
As, 1 atom require charge to deposited =
Number of atoms deposited =
atoms
Now we have to calculate the number of moles deposited.
Number of moles deposited =
moles
Now we have to calculate the mass of copper deposited.
1 mole of Copper has mass = 63.5 g
Mass of Copper Deposited = ![63.5\times 0.03113 =1.98g](https://tex.z-dn.net/?f=63.5%5Ctimes%200.03113%20%3D1.98g)
Therefore, the mass of copper deposit is, 1.98 grams