Answer:

Explanation:
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In this case, for these types of acid-base neutralizations, it is crucial to firstly set up the chemical reaction taking place between the acid and the base; in this case HCl and Mg(OH)2 respectively, whose products are obtained by switching around the anions and cations as shown below:

Which must be balanced to accurately predict the mole ratio on the reactants side:

Whereas we can see a 2:1 mole ratio of the acid to the base; thus, the moles of Mg(OH) required for the neutralization of 6.0 moles of HCl turn out to be:

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Option are as follow,
A. temperature, concentration and surface area
<span>B. temperature, and concentration only </span>
<span>C. concentration and surface area only </span>
<span>D. temperature and surface area only
</span>
Answer:
Option-<span>A. Temperature, Concentration and Surface area
</span>
Explanation:
1) Increasing Temperature:
Increase in temperature increases the Kinetic energy of molecules. This results in increase in the velocity and rate of collisions between reactants. Hence, greater the number of collisions between reactants per time greater will be the probability of formation of product per unit time.
2) Increasing Concentration
Increase in concentration results in increase in number of particles of reactants per unit area, hence collision rate increases resulting in rate of reaction.
3) Increasing Surface Area
Grinding of Zn results in the increase of surface area of Zinc. So greater the surface area greater is the exposure of Zinc metal to HCl molecules, hence the rate of formation of product increases.
The mass of 2.80 grams of h2o is 18.02 amu I believe
Answer:
K = 137.55 atm/M.
Explanation:
- The relationship between gas pressure and the concentration of dissolved gas is given by Henry’s law:
<em>P = (K)(C)</em>
where P is the partial pressure of the gaseous solute above the solution (P = 1.0 atm).
k is a constant (Henry’s constant).
C is the concentration of the dissolved gas (C = 7.27 x 10⁻³ M).
∴ K = P/C = (1.0 atm)/(7.27 x 10⁻³ M) = 137.55 atm/M.