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2 years ago

12

The tire pressure in a automobile tire was 2.38 atm when the tire was at 26°C. As the automobile drove for several hours, the te

mperature of the tire increased to 93°C.
35 atm

41.0 atm

2.91 atm

3.09 atm

33 atm

1 answer:

diamong [38]2 years ago

6 0

Answer:

The answer is 2.91 atm

Explanation:

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Discharge is measured in cubic meters per second.

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A government laboratory wants to determine whether water in a certain city has any traces of fluoride and whether the concentrat

nexus9112 [7]

<u>Answer:</u> The given sample of water is not safe for drinking.

<u>Explanation:</u>

We are given:

Concentration of fluorine in water recommended = 4.00 ppm

ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of fluorine in water, we use the equation:

$\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Both the masses are in grams.

We are given:

Mass of fluorine = $0.152mg=0.152\times 10^{-3}g$ (Conversion factor: 1 g = 1000 mg)

Mass of water = 5.00 g

Putting values in above equation, we get:

$\text{ppm of fluorine in water}=\frac{0.152\times 10^{-3}}{5}\times 10^6\\\\\text{ppm of fluorine in water}=30.4$

As, the calculated concentration is greater than the recommended concentration. So, the given sample of water is not safe for drinking.

Hence, the given sample of water is not safe for drinking.

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2 years ago

A 10.0 mL sample of household ammonia solution required38.50 mL of 0.311 M HCl to achieve neutralization. Calculate (a).the mola

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Answer:

a) 1.1974 M

b) 2.07%

Explanation:

In this case, we have a neutralization reaction between the HCl and ammonia, the acid base reaction is as follow:

HCl + NH₃ --------> NH₄⁺ + Cl⁻

a) As we can see, we have a 1:1 mole ration between the acid and the base, therefore we can use the following expression to calculate concentration of the ammonia:

M₁V₁ = M₂V₂

Replacing the data in here, we can solve for the concentration of ammonia:

M₂ = M₁V₁ / V₂

M₂ = 0.311 * 38.50 / 10

M₂ = 1.1974 M

This is the concentration of the ammonia solution.

b) Now we want to know the mass percent, in this case, we need to calculate the moles of ammonia first, and then, turn it into mass using the molar mass given (17 g/mol):

n = 1.1974 * 0.010 = 0.011974 moles

m = 0.011974 * 17 = 0.2036 g

The solution has a density of 0.983 g/mL and we have 10 mL therefore, we should have of mass:

d = m/V

m = d * V

m = 0.983 * 10 = 9.83 g

Finally the mass percent will be:

% = 0.2036 / 9.83 * 100

% = 2.07%

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3 years ago

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We know, Given mass = Molar mass * Number of moles.

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Hope this helps!

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2 years ago