1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mazyrski [523]
2 years ago
12

The tire pressure in a automobile tire was 2.38 atm when the tire was at 26°C. As the automobile drove for several hours, the te

mperature of the tire increased to 93°C.
35 atm

41.0 atm

2.91 atm

3.09 atm

33 atm​
Chemistry
1 answer:
diamong [38]2 years ago
6 0

Answer:

The answer is 2.91 atm

Explanation:

You might be interested in
Please help! i will mark as brainliest
beks73 [17]

Answer:

Most of the food energy that enters a trophic level is "lost" as heat when it is used by organisms to power the normal activities of life. Thus, the higher the trophic level on the pyramid, the lower the amount of available energy.

Explanation:

8 0
2 years ago
Read 2 more answers
The picture shows two liquid samples are poured into a beaker. As shown, the liquids don’t mix with each other. Which statement
Nesterboy [21]

The answer is A. The volume lines on the bottom are just showing the volume of the beaker. The more dense liquid will sink to the bottom
7 0
3 years ago
The conversion factor relating feet to meters is 1ft=0.305m. Keep in mind that when using conversion factors, you want to make s
const2013 [10]

Answer: 1,762.97 ft² ≈ 1,763 ft²


Explanation:


1) Conversion factor:


1 ft = 0.305m ⇒


1 = 1 ft / 0.305m ⇒


´[1]² = [1 ft / 0.305m]² ⇒


1 = 1 ft² / (0.305m)² ⇒


1 = 1 ft² / 0.093025 m²


2) 164 m²


164 m² × 1 ft² / 0.093025 m² = 1,762.97 ft² ≈ 1,763 ft²




5 0
3 years ago
Read 2 more answers
A. 14.8
Scilla [17]

Answer:

Explanation:

1)

Given data:

Initial volume  = 2.5 L

Initial temperature = 300 k

Final temperature = 80 k

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 2.5 L × 80 K / 300 k

V₂ = 200 L.K / 300 K

V₂ = 0.67 L

2)

Given data:

Initial volume  = 752 mL

Initial temperature = 25.0°C (25+273 = 298 K)

Final temperature = 50.0°C(50+273 = 323 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 752 mL × 323 K / 298 k

V₂ = 242896 mL.K / 298 K

V₂ = 815.1  mL

3)

Given data:

Initial volume  = 2.75 L

Initial temperature = 20°C (20+273 = 293 K)

Final temperature = ?

Final volume = 2.46 L

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂  = V₂T₁/V₁

T₂ = 2.46 L × 293 K / 2.75  L

T₂ = 720.78 L.K /  2.75 L

T₂ = 262.1 K

4)

Given data:

Initial volume  = 1500 L

Initial temperature = 5°C (5+273 = 278 K)

Final temperature = 30 °C(30+273 = 303 K)

Final volume of heated air = ?

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1500 L × 303 K / 278 k

V₂ = 454500 L.K / 278 K

V₂ = 1634.89  L

5)

Given data:

Initial volume = 15.5 L

Initial temperature = 20°C (20+273 = 293 K)

Final temperature = 7.0 °C(7.0+273 = 280 K)

Final volume of balloon = ?

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 15.5 L × 280 K / 293 k

V₂ = 4340 L.K / 293 K

V₂ = 14.8  L

6)

Given data:

Initial volume = 150 mL

Initial temperature = 23.5°C (23.5+273 = 296.5 K)

Final temperature = 72.5 °C(72.5+273 = 345.5 K)

Final volume of balloon = ?

Solution:

The given problem will be solve through the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 150 mL × 345.5 K / 296.5 k

V₂ = 51825 mL.K / 296.5 K

V₂ = 174.79  mL

6 0
3 years ago
Will mark first correct answer brainliest
olganol [36]

Answer:

it does not show the actual number of atoms in that molecule

5 0
2 years ago
Other questions:
  • How do the valence electron configurations of alkali metals compared with each other?
    7·1 answer
  • After being thoroughly stirred at 10.°C, which mixture is heterogenous?(1) 25.0 g of KCl and 100. g of H2O
    5·1 answer
  • Which process uses acetyl coa as a reactant? apex?
    5·1 answer
  • What types of isomerism are exhibited by the coordination complex [co(dppe)(net3)2cl2] ?
    12·1 answer
  • CS3PO4 + Na2SO4 → Na3PO4 + Cs2SO4​
    15·1 answer
  • 16 meters per hour to miles per sec
    14·1 answer
  • Which of the following is classified as a ionic compound
    8·1 answer
  • Which of the following would least likely be found in a wide valley?
    14·2 answers
  • Explain why a steel object continues to rust even after its outer layers have corroded.
    6·1 answer
  • You are visiting your Great Aunt Agnes. She is about 65 years
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!