True or False: Different substances, like shortening and soap, will melt at the same temperature. True False

Chemistry

2 answers:

stiks02 [169]3 years ago

8 0

Answer: true

explanation:

Murrr4er [49]3 years ago

7 0

Answer:

false

Explanation:

different things will have different melting points

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Calculate the molarity of a solution that contains 200 g of copper (II) chloride( CuCl2) in 150 mL of solution.

Yuliya22 [10]

I think it’s letter C or D

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3 years ago

What volume of .100 M HCl is required to titrate .100 g of sodium bicarbonate to its equivalence point?

Karo-lina-s [1.5K]

The reaction is: HCl + Na HCO3 → NaCl + H2CO3, which is already balanced.

Then the molar ratios are 1 mol HCL : 1 mol NaHCO3

You know the mass of NaHCO3 is 0.100 g, then you can find the number of moles using the molar mass of NaHCO3

molar mass of NaHCO3 is 23 g/mol + 1 g/mol + 12g/mol + 3*16g/mol = 84 g/mol

And the number of moles is: 0,100 g / 84 g/mol = 0,0012 mol of NaHCO3.

Then, from the ratio 1:1, you know that, at the titration point, the number of moles of HCl is the same: 0,0012 mol of HCl.

Now from the fomula of molarity you have: M = #of moles / V in liters

=> V in liters = # of moles / M = 0.0012 mol / 0.100 M = 0.012 liters

Answer: 0.012 liters of HCL

6 0

4 years ago

Read 2 more answers

ASAP WILL GIVE BRAINLIEST!!

Nataly_w [17]

Answer:

The answer to your question is a) N₂ b) 3.04 g of NH₃

Explanation:

Data

mass of H₂ = 2.5 g

mass of N₂ = 2.5 g

molar mass H₂ = 2.02 g

molar mass of N₂ = 28.02 g

molar mass of NH₃ = 17.04 g

Balanced chemical reaction

3H₂ + 1 N₂ ⇒ 2NH₃

Calculate the theoretical yield 3H₂ / N₂ = 3(2.02) / 28.02 = 0.22

Calculate the experimental yield H₂/N₂ = 2.5/2.5 = 1

Conclusion

The limiting reactant is N₂ (nitrogen) because the experimental proportion was higher than the theoretical proportion.

28.02 g of N₂ -------------------- (2 x 17.04) g of NH₃

2.5 g of N₂ -------------------- x

x = (2.5 x 2 x 17.04) / 28.02

x = 85.2 / 28.02

x = 3.04 g of NH₃

6 0

3 years ago

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melisa1 [442]

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