Un patinador recorre un parque de 7.2 km de largo a una velocidad de 5 m/s ?cuantas horas duro su recorrido?
2 answers:
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Answer:
In statics condition and if is a body is over plane surface N = mg
In all cases which a body is on a ramp force N will be smaller than mg, and depending on the level of the ramp (bigger the ramp smaller force N)
Explanation:
See annex (Figure 1)
We can see with the help of force diagram the relation between N force and mg
Lets look first the body on the ramp assuming there is not movement
The sum of forces alog y axis = 0
mg* cos∠ BAC = N (normal force)
So N is always a fuction of mg and of the cosine of the inclination angle, and the cosine of angle varies from value 1 when the angle is 0 (look the case where the block is on the surface without inclination N = mg ).
And as the inclination increase the value of cosine will become smaller and so will N force which is directly proportional of cosine of the inclination angle
Therefore we can say that force N is always minor than mg unless in extreme case where the block is over the surface in which case N takes its maximum value N = mg
Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.
An electron is released from rest at a distance of 0 m from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² . How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?
Answer:
Work=1.06×10⁻²¹J
Explanation:
Given Data
Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²
Charge density σ=3.90×10⁻¹² C/m²
The electron moves a distance d=3.00×10⁻²m
Electron charge e=-1.6×10⁻¹⁹C
To find
Work done
Solution
The electric field due is sheet is given as
E=σ/2ε₀
Now we need to find force on electron
Now for Work done on the electron