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lorasvet [3.4K]
3 years ago
12

1.) an object moves along the x axis, subject to the potential energy shown. The object has a mass of 1.1kg and starts at rest a

t point A. (a) what is the object’s speed at point B? (b) at point C? (c) at point D? (d) what are the turning points for this object?
2.) a 1250-kg car drives up a hill that is 16.2m high. During the drive, two nonconservative forces do work on the car: (i) the force of friction, and (ii) the force generated by the car’s engine. The work done by friction is -3.11x10^5J; the work done by the engine is +6.44x10^5J. find the change in the car’s kinetic energy from the bottom of the hill to the top of the hill.
3.) starting at rest at the edge of a swimming pool, a 72.0-kg athlete swims along the surface of the water and reaches a speed of 1.20m/s by doing the work Wncl=+161J. find the nonconservative work, wnc2, done by the water on the athlete.
4.) starting at rest at the edge of a swimming pool, a 72.0-kg athlete swims along the surface of the water and reaches a speed of 1.20m/s by doing the work Wncl=+161J. find the nonconservative work, wnc2, done by the water on the athlete.
Physics
1 answer:
MrRa [10]3 years ago
4 0
If I'm not wrong #1 should be C
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A 920-kg compact car moving at 92 m/s has approximately 3,893,440 Joules of kinetic energy. What is the change in kinetic energy
tensa zangetsu [6.8K]

Answer:

Change in kinetic energy = 3297280 J

Explanation:

Given that,

Mass, m = 920 kg

Speed of a car, v = 92 m/s

Kinetic energy, K = 3,893,440 J

If the speed of a car, V = 36 m/s

Net kinetic energy is given by :

K_n=\dfrac{1}{2}mV^2\\\\=\dfrac{1}{2}\times 920\times (36)^2\\\\K_n=596160\ J

The change in kinetic energy = 3,893,440 - 596160

= 3297280 J

So, the change in kinetic energy of the car is 3297280 J.

3 0
2 years ago
A floating ice block is pushed through a displacement d = (23 m) i - (9 m) j along a straight embankment by rushing water, which
Sav [38]

Answer:

Work = 5941 J

Explanation:

As we know that work done is given by the equation

W = F. d

here we know that

F  = (200 N)\hat i - (149 N) \hat j

also we have

d = (23m) \hat i - (9 m)\hat j

now from above formula we have

W = (200 N\hat i - 149 N \hat j).(23 m\hat i - 9m \hat j)

W = 5941 J

3 0
3 years ago
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3 years ago
To practice Problem-Solving Strategy 16.1 Standing waves. An air-filled pipe is found to have successive harmonics at 800 HzHz ,
bazaltina [42]

Answer:

Length of the pipe = 53.125 cm

Explanation:

given data

harmonic frequency f1  = 800 Hz

harmonic frequency f2  = 1120 Hz

harmonic frequency f3  = 1440 Hz

solution

first we get here fundamental frequency that  is express as

2F = f2 - f1    ...............1

put here value

2F = 1120 - 800

F = 160 Hz

and

Wavelength is express as

Wavelength  = Speed ÷ Fundamental frequency    ................2

here speed of waves in air  = 340 m/s

so put here value

Wavelength  =340 ÷ 160

Wavelength   = 2.125 m

so

Length of the pipe will be

Length of the pipe = 0.25 × wavelength    ......................3

put here value

Length of the pipe = 0.25 × 2.125

Length of the pipe = 0.53125 m

Length of the pipe = 53.125 cm

7 0
3 years ago
Two spherical objects have equal masses and
ehidna [41]

to your question is 54 cm
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