1.) an object moves along the x axis, subject to the potential energy shown. The object has a mass of 1.1kg and starts at rest a
1 answer:
You might be interested in
In a series circuit the total current is the same throughout resistors and so:
The voltage is distributed throughout the resistors and so:
and the total resistance can be calculated by adding up the resistors resistance:
First thing is to calculate the total resistance and so:
And by Omh's law V=IR we have:
And so the total current of the circuit is 1.2 amps i.e. 1.2 A.
Answer:
a)
b)
c) 0 J/K
d)S= 61.53 J/K
Explanation:
Given that
T₁ = 745 K
T₂ = 101 K
Q= 7190 J
a)
The entropy change of reservoir 745 K
Negative sign because heat is leaving.
b)
The entropy change of reservoir 101 K
c)
The entropy change of the rod will be zero.
d)
The entropy change of the system
S= S₁ + S₂
S = 71.18 - 9.65 J/K
S= 61.53 J/K
The Earth's rotational kinetic energy is the kinetic Energy that the Earth
has due to rotation.
The rotational kinetic energy of the Earth is approximately <u>3.331 × 10³⁶ J</u>
Reasons:
<em>The parameters required for the question are; </em>
<em>Mass of the Earth, M = </em><em>5.97 × 10²⁴ kg</em>
<em>Radius of the Earth, R = </em><em>6.38 × 10⁶ m</em>
<em>The rotational period of the Earth, T = </em><em>24.0 hrs</em><em>.</em>
Which gives;
Therefore;
Which gives;
The rotational kinetic energy of the Earth, = <u>3.331 × 10³⁶ Joules</u>
Learn more here:
<em>The moment of inertia from part A of the question (obtained online) is that of the Earth approximated to a perfect sphere</em>.
<em>Mass of the Earth, M = 5.97 × 10²⁴ kg</em>
<em>Radius of the Earth, R = 6.38 × 10⁶ m</em>
<em>The rotational period of the Earth, T = 24.0 hrs</em>