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lorasvet [3.4K]
3 years ago
12

1.) an object moves along the x axis, subject to the potential energy shown. The object has a mass of 1.1kg and starts at rest a

t point A. (a) what is the object’s speed at point B? (b) at point C? (c) at point D? (d) what are the turning points for this object?
2.) a 1250-kg car drives up a hill that is 16.2m high. During the drive, two nonconservative forces do work on the car: (i) the force of friction, and (ii) the force generated by the car’s engine. The work done by friction is -3.11x10^5J; the work done by the engine is +6.44x10^5J. find the change in the car’s kinetic energy from the bottom of the hill to the top of the hill.
3.) starting at rest at the edge of a swimming pool, a 72.0-kg athlete swims along the surface of the water and reaches a speed of 1.20m/s by doing the work Wncl=+161J. find the nonconservative work, wnc2, done by the water on the athlete.
4.) starting at rest at the edge of a swimming pool, a 72.0-kg athlete swims along the surface of the water and reaches a speed of 1.20m/s by doing the work Wncl=+161J. find the nonconservative work, wnc2, done by the water on the athlete.
Physics
1 answer:
MrRa [10]3 years ago
4 0
If I'm not wrong #1 should be C
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B. a generator

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What is an asteroid that is pulled off course by a planet’s gravity and orbits around that planet called?
tresset_1 [31]

The definition of the celestial bodies allows us to find that the correct answer for a body that is captured and is in planetary orbit is:

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Asteroids are small rocky bodies that rotate around the Sun, when this body enters the atmosphere of a planet and reaches the surface it is called meteoroids.

A meteorite is a fragment of meteoroid, which has been divided in space or the atmosphere during the entrance to the planet, in general they are smaller

A meteor is the atmospheric phenomenon that occurs when the pattern meteorite or meteoroid enters, that is, it does not correspond to a celestial body.

An asteroid satellite or Moon is a celestial object that revolves captures and around another asteroid, this concept can be extended to an asteroid revolving captures and around a planet

A satellite is a celestial body that orbits a planet, its origin is varied and could be formed during the formation of the planet itself, or by capturing a nearby body during the initial formation of the solar system.

Let's examine the different answers

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True. A body captured by a planet is generally called the Moon.

  • Meteoriode.

False. A meteoroid is a body that enters the atmosphere of the plant and reaches its surface.

  • Meteorite

False. It is a fragment of meteoroid that manages to reach the surface of the planet.

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False.   Atmospheric phenomenon visible when passing a meteoroid or meteorite.

In conclusion, using the definition of celestial bodies we can find that the correct answer for a body that is captured and is in planetary orbit is:

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Learn more here: brainly.com/question/3889451

4 0
3 years ago
Ball A was carried to the top of a hill in a straight line, while ball B was carried in a longer, zigzag path. At the top of the
marissa [1.9K]

Answer: equal

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A river flows due east at 1.60 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
Citrus2011 [14]

Answer:

part (a) v\ =\ 10.42\ at\ 81.17^o towards north east direction.

part (b) s = 46.60 m

Explanation:

Given,

  • velocity of the river due to east = v_r\ =\ 1.60\ m/s.
  • velocity of the boat due to the north = v_b\ =\ 10.3\ m/s.

part (a)

River is flowing due to east and the boat is moving in the north, therefore both the velocities are perpendicular to each other and,

Hence the resultant velocity i,e, the velocity of the boat relative to the shore is in the North east direction. velocities are the vector quantities, Hence the resultant velocity is the vector addition of these two velocities and the angle between both the velocities are 90^o

Let 'v' be the velocity of the boat relative to the shore.

\therefore v\ =\ \sqrt{v_r^2\ +\ v_b^2}\\\Rightarrow v\ =\ \sqrt{1.60^2\ +\ 10.3^2}\\\Rightarrow v\ =\ 10.42\ m/s.

Let \theta be the angle of the velocity of the boat relative to the shore with the horizontal axis.

Direction of the velocity of the boat relative to the shore.\therefore Tan\theta\ =\ \dfrac{v_b}{v_r}\\\Rightarrow Tan\theta\ =\ \dfrac{10.3}{1.60}\\\Rightarrow \theta\ =\ Tan^{-1}\left (\dfrac{10.3}{1.60}\ \right )\\\Rightarrow \theta\ =\ 81.17^o

part (b)

  • Width of the shore = w = 300m

total distance traveled in the north direction by the boat is equal to the product of the velocity of the boat in north direction and total time taken

Let 't' be the total time taken by the boat to cross the width of the river.\therefore w\ =\ v_bt\\\Rightarrow t\ =\ \dfrac{w}{v_b}\\\Rightarrow t\ =\ \dfrac{300}{10.3}\\\Rightarrow t\ =\ 29.12 s

Therefore the total distance traveled in the direction of downstream by the boat is equal to the product of the total time taken and the velocity of the river\therefore s\ =\ u_rt\\\Rightarrow s\ =\ 1.60\times 29.12\\\Rightarrow s\ =\ 46.60\ m

7 0
3 years ago
A carbon fiber car bumper is hit by another car with the stress of 106,483 Pa. If carbon fiber has a Young's modulus of 228 x 10
hoa [83]

Answer:

Stress = 4.67 * 10^-7 N/m²

Explanation:

Young's modulus of the material = Stress/Strain

Given

Young's modulus  = 228 x 10^9 Pa

Stress =  106,483 Pa

Required

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From the formula;

Strain = Stress/Young modulus

Strain =  106,483 /228 x 10^9

Stress = 4.67 * 10^-7 N/m²

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