Answer:
880 kg / m^3
Explanation:
height of column of oil = 85 cm = 0.85 m
height of column of mercury = 5.5 cm = 0.055 m
Density of mercury = 13600 kg/m^2
Let teh density of oil is d.
A the height of mercury column is balanced by the height of oil column
So, the pressure due to the mercury column = pressure by teh oil column
height of mercury column x density of mercury x g = height of oil column
x density of oil x g
0.055 x 13600 x g = 0.85 x d x g
748 = 0.85 d
d = 880 kg / m^3
Answer:
The correct answer is
d. An iron cage
Max Weber is well known for developing the theoretical concept of the iron cage
Explanation:
The theory of the iron was first presented by the sociologist Max Weber in the work The Protestant Ethic and the Spirit of Capitalism.
Here Weber clarified that with the diminishing effect of Protestantism within our social life the capitalist system remained as well as the bureaucratic principles and social structures that came about along with came along with it, such the worldviews and values becomes major controlling factors in socil life which is tantamount to living in a strong house maade of steel
The speed of the second mass after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
<h3>
What are we to consider in equilibrium ?</h3>
Whenever the friction in the pulley is negligible, the two blocks will accelerate at the same magnitude. Also, the tension at both sides will be the same.
Given that a large mass m1=5.75 kg and is attached to a smaller mass m2=3.53 kg by a string and the mass of the pulley and string are negligible compared to the other two masses. Mass 1 is started with an initial downward speed of 2.13 m/s.
The acceleration at which they will both move will be;
a = ( - ) / ( + )
a = (5.75 - 3.53) / (5.75 + 3.53)
a = 2.22 / 9.28
a = 0.24 m/s²
Let us assume that the second mass starts from rest, and the distance covered is the h = 2.47 m
We can use third equation of motion to calculate the speed of mass 2 after it has moved ℎ=2.47 meters.
v² = u² + 2as
since u =0
v² = 2 × 0.24 × 2.47
v² = 1.1856
v = √1.19
v = 1.0888 m/s
Therefore, the speed of mass 2 after it has moved ℎ=2.47 meters will be 1.09 m/s approximately
Learn more about Equilibrium here: brainly.com/question/517289
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