Answer: 0.16Hz
Explanation:
Given that:
wavelength (λ) = 125 meters
speed (V) = 20 m/s
frequency (F) = ?
Recall that frequency is the number of cycles the wave complete in one second. And its value depends on the wavelength and speed of the wave.
So, apply the formula V = F λ
Make F the subject formula
F = V / λ
F = 20 m/s / 125 meters
F = 0.16 Hz
Thus, the frequency of the wave is 0.16 Hertz.
Answer:
The current in the second loop will stay constant
Explanation:
Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)
Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.
So, i₂R = -Mdi₁/dt
i₂ = -Mdi₁/dt/R
Since di₁/dt = + 1 A/s,
i₂ = -Mdi₁/dt/R
i₂ = -M × + 1 A/s/R
i₂ = -M/R
Since M and R are constant, this implies that i₂ = constant
<u>So, the current in the second wire loop will stay constant.</u>
Answer:
The correct option is;
The star is moving toward Earth.
Explanation:
The shifting of the wavelength of light wave toward the blue end of the electromagnetic spectrum is termed blue shift.
A blue-shift of an electromagnetic wave corresponds to the wavelength decrease of the wave, which is equivalent increase in energy, resulting in an increase in the observed frequency of the wave.
Astronomers make use of the shifting of the wavelength of a wave to understand the relative motion of galaxies.
The wavelength of an approaching electromagnetic ave shifts towards the blue end of the electromagnetic spectrum because the wavelength is shorter.
The opposite of phenomenon is red-shift.
Energy=mass*SHC*temp change
=100*0.9*75
=6750J
Answer:
Explanation:
The speed of the bullet will only be the same if the mass of the bullet is equal to the mass of the gun. This because only their momentum ( product of mass and velocity) is conserved; the momentum before the gun and pullet was fired is equal to the momentum of the recoil of the gun and the momentum of the released bullet. The smallest mass receives the highest speed (the bullet) while the larger mass ( the gun) receives the lowest speed ( speed of recoil).
