Answer:
x^3-10x^2+x+120
Step-by-step explanation:
Assuming you mean roots -3, 5, 8
These happen when we have (x+3)(x-5)(x-8)=0
Expand this
(x^2-2x-15)(x-8)=0
=x^3-2x^2-15x-8x^2+16x+120
=x^3-10x^2+x+120
Since, population of species A is represented by :
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e.,
i.e.,
i.e.,
Also, since population of species B is represented by :
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e.,
i.e.,
i.e.,
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
Answer:
$507.00.
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 6.5%/100 = 0.065 per year,
then, solving our equation
I = 1300 × 0.065 × 6 = 507
I = $ 507.00
The simple interest accumulated
on a principal of $ 1,300.00
at a rate of 6.5% per year
for 6 years is $ 507.00.