Answer:
Ethane can be ionized
Explanation:
Ionization or ionisation is the process by which an atom or a molecule acquires a negative or positive charge by gaining or losing electrons, often in conjunction with other chemical changes. The resulting electrically charged atom or molecule is called an ion.
hope this helps out!
<em>~</em><em>A</em><em>d</em><em>r</em><em>i</em><em>a</em><em>n</em><em>n</em><em>a</em>
4: The mass amount of protons and neutrons in an atom
We just covered this in my chem class
Answer:

Explanation:
The balanced equation is
I₂(g) + Br₂(g) ⇌ 2IBr(g)
Data:
Kp = 280
p(IBr) = 0.200 atm
1. Set up an ICE table.
Let p = the initial pressure of IBr. Then

2. Calculate p(I₂)
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Check:

Structure along with ¹H-NMR is shown below.
Signal for Hₐ; Based on multiplicity of of the peak, a
Singlet peak (the only singlet peak present in spectrum) at
2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.
Signal for Hb; Based on multiplicity of of the peak, a
Quartet peak (the only quartet peak present in spectrum) at
2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.
Signal for Hc; Based on multiplicity of of the peak, a
Triplet peak (the only triplet peak present in spectrum) at
1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.
Answer:
1.20 V
Explanation:

Here Pb undergoes oxidation by loss of electrons, thus act as anode. Bromine undergoes reduction by gain of electrons and thus act as cathode.

Where both
are standard reduction potentials.
Given,

![E^0_{[Pb^{2+}/Pb]}= -0.13\ V](https://tex.z-dn.net/?f=E%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D%3D%20-0.13%5C%20V)

![E^0_{[Br_2/Br^{-}]}=+1.07\ V](https://tex.z-dn.net/?f=E%5E0_%7B%5BBr_2%2FBr%5E%7B-%7D%5D%7D%3D%2B1.07%5C%20V)
![E^0=E^0_{[Br_2/Br^{-}]}- E^0_{[Pb^{2+}/Pb]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BBr_2%2FBr%5E%7B-%7D%5D%7D-%20E%5E0_%7B%5BPb%5E%7B2%2B%7D%2FPb%5D%7D)
