Mass of Gold = 267.165 × 0.01552494829
⇒ 4.1477228099
The amount of heat(q) required to raise m grams of a substance-specific C from T1 to T2 is given by
q=m C (T2-T1) ........1
Given : q= 2.1200 J
the initial temperature of gold, T1 = 22.0Celcius
the final temperature of gold, T2 = 1064.4Celcius
specific heat of gold = 0.131
putting values in eq 1:
⇒ 2.1200 = m × 0.131 × (1064.4-22)
⇒ 2.1200 = m × 0.131 × 1042.4
⇒ 2.1200 / 136.5544
⇒ 0.01552494829
Since 1g= 0.01552494829 Pounds
Mass of Gold = 267.165 × 0.01552494829
⇒ 4.1477228099
Learn more about temperature here: brainly.com/question/11464844
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<span>4.9 L would be the answer to this question :)</span>
Answer:
131.8 g.
Explanation:
- There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):
<u><em>d = m / V.</em></u>
d = 0.8787 g/ml.
V = 0.15 L x 1000 = 150 ml.
- ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
It’s because new discoveries are made all the time sometimes what was considered right may be found out to be wrong
