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3 years ago

How do isotopes of the same atom react chemically? How do isotopes of the same atom compare in size?

1 answer:

7 0

Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.

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A mixture of A and B is capable of being ignited only if the mole percent of A is 6 %. A mixture containing 9.0 mole% A in B flo

atroni [7]

Explanation:

As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.

Hence, calculate the molecular weight of the mixture as follows.

Weight = $0.09 \times 16.04 + 0.91 \times 29$

= 27.8336 g/mol

And, molar flow rate of air and mixture is calculated as follows.

$\frac{800}{27.8336}$

= 28.74 kmol/hr

Now, applying component balance as follows.

$0.09 \times 28.74 + 0 \times F_{B} = 0.06F_{p}$

$F_{p}$ = 43.11 kmol/hr

$F_{A} + F_{B} = F_{p}$

$F_{B}$ = 43.11 - 28.74

= 14.37 kmol/hr

So, mass flow rate of pure (B), is $F_{B}$ = $14.37 \times 29$

= 416.73 kg/hr

According to the product stream, 6 mol% A and 94 mol% B is there.

Molecular weight of product stream = $Mol. weight \times 43.11 kmol/hr$

= $0.06 \times 16.04 + 0.94 \times 29$

= 28.22 g/mol

Mass of product stream = 1216.67 kg/hr

Hence, mole of $O_{2}$ into the product stream is as follows.

$0.21 \times 0.94 \times 43.11$

= $8.5099 kmol/hr \times 329 g/mol$

= 272.31 kg/hr

Therefore, calculate the mass % of $O_{2}$ into the stream as follows.

$\frac{272.31}{1216.67} \times 100$

= 22.38%

Thus, we can conclude that the required flow rate of B is 272.31 kg/hr and the percent by mass of $O_{2}$ in the product gas is 22.38%.

4 0

3 years ago

Which is the most to least soluble: NH3, NBr3, N2

Rom4ik [11]

Answer: https://quizlet.com/368481219/chem-2052-1-flash-cards/

I hope this helps! if not contact me for more help

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3 years ago

Gas-to-liquid synfuel production can produce diesel, naptha and paraffin. The formation of these products usually involves _____

Goshia [24]

The best and most correct answer among the choices provided by the question is the second choice. The formation of gas-to-liquid synfuel usually involves the removal of carbon atoms from the fuel adding highly acidic substances such as hydrochloric acid. I hope my answer has come to your help. God bless and have a nice day ahead!

3 0

3 years ago

Read 2 more answers

Draw the structures of two stereoisomeric alkenes that would give 3-hexanol as the only major product of hydroboration

larisa [96]

Answer:

Cis- and trans-3-hexene are symmetric hydrocarons that give only one major product i.e 3-hexanol upon hydroboration.

Explanation:

During hydroboration of 3-hexene, borane (BH3) is added to the double bond of hexene, that transfers the hydrogen atoms to that carbon which becomes is bonded to the boron. The process of hydroboration is created in two steps that leads to the formation of 3-hexanol and boric acid. (please see figure)

Now, the two stereoisomers, Cis- and trans-3-hexene both will give off the 3-hexanol upon hydroboration and the structure of these are illustrated in the figure.

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3 years ago

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Fill in the blanks for the drawing of a voltaic cell that’s made with copper/copper (II) nitrate (E° = 0.34 V) and zinc/zinc (II

Elodia [21]

Answer:

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Explanation:

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3 years ago