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Brums [2.3K]
2 years ago
15

[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev

erberation time with 800 audiences. Wait​
Physics
1 answer:
Lilit [14]2 years ago
4 0

The reverberation time with 800 audiences is 0.875 seconds.

<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

  • R₁ is the reverberation time with 400 audience
  • R₂ is the reverberation time with 800 audience
  • V₁ is initial volume
  • V₂ is final volume

R₂ = R₁V₁/V₂

R₂ = (1.4 x 500) / 800

R₂ = 0.875 seconds

Thus, the reverberation time with 800 audiences is 0.875 seconds.

Learn more about reverberation time here: brainly.com/question/9278479

#SPJ1

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Holding onto a tow rope moving parallel to a frictionless ski slope, a 68.7 kg skier is pulled up the slope, which is at an angl
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Explanation:

a) Let consider two equations of equilibrium, the first parallel to ski slope and the second perpendicular to that. The equations are, respectively:

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The force on the skier is:

F = m \cdot g \cdot \sin \theta

F = (68.7\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \sin 6.7^{\textdegree}

F = 78.606\,N

b) The equations of equilibrium are the following:

\Sigma F_{x'} = F - m\cdot g \cdot \sin \theta = m\cdot a\\\Sigma F_{y'} = N - m\cdot g \cdot \cos \theta = 0

The force on the skier is:

F = m\cdot (a + g \cdot \sin \theta)

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3 0
3 years ago
An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If y
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Answer:

The fraction of the protons would have no electrons =1.88\times 10^{-10}

Explanation:

We are given that

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Electrons are fewer than protons=1.88\times 10^6

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

=\frac{Fewer\;electrons}{Total\;protons}

The fraction of the protons would have no electrons

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=1.88\times 10^{-10}

Hence, the fraction of the protons would have no electrons =1.88\times 10^{-10}

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