The actual neutralization reaction between the acid and base is H+ + OH- = H2O and this is what the -56 kJ/mole applies to
Then work out how much reactants you have
0.150 L * 0.50 mole/L = 0.075 mole for HCl
0.050 L * 1.00 mole/L = 0.050 mole for NaOH
So the HCl is in excess and the NaOH will all react. The energy released is -56 kJ/mole * 0.050 mole = -2.8 kJ or -2800 J
Temperature changes of solid, liquids or gas are calculated using:
energy = mass * heat capacity * (initial temperature - final temperature)
-2800 J = 200g * 4.18 J/gC * (53.9C - Tf)
Tf = 57.25 C. Rounded off I would say 57.3 C
Would be na I did the quiz and I got it right so it would be c your welcome give me brainliest
1. that mass
2. a particle that has the same properties at every point
Ionization energies evidence for the quantization of energy levels in atoms, as described by the Schrodinger wave mechanical model of the atom because it takes a specific amount of energy to remove the definite one electron from an atom.
Explanation:
- Ionization energies evidence for the quantization of energy levels in atoms, as described by the Schrodinger wave mechanical model of the atom because it takes a specific amount of energy to remove the definite one electron from an atom.
- There is an approximate amount of energy which is needed to overcome the attractive force between the electrons and nucleus.
- If you put less than the required ionization energy, then the electrons can not be removed.
Answer:
1.5×10⁷ Hz
Explanation:
From the question given above, the following data were obtained:
Wavelength of radio wave (λ) = 20 m
Frequency (f) =?
Frequency and wavelength of a wave are related by the following equation:
v = λf
Where:
'v' is the velocity of electromagnetic wave.
'λ' is the wavelength
'f' is the frequency.
With the above formula, we can obtain the frequency of the radio wave as illustrated below:
Wavelength of radio wave (λ) = 20 m
Velocity (v) = 3×10⁸ m/s
Frequency (f) =?
v = λf
3×10⁸ = 20 × f
Divide both side by 20
f = 3×10⁸ / 20
f = 1.5×10⁷ Hz
Thus the frequency of the radio wave is 1.5×10⁷ Hz
