9514 1404 393
Answer:
x = 6
Step-by-step explanation:
The sum of segments is used:
EF +FG = EG
3x +(5x +16) = 11x -2 . . . . substitute given expressions
8x +18 = 11x . . . . . . . . add 2
18 = 3x . . . . . . . . subtract 8x
6 = x . . . . . . divide by 3
The value of the variable is 6.
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<em>Check</em>
The segment lengths are ...
EF = 3x = 3·6 = 18
FG = 5x+16 = 5·6 +16 = 46
EG = 11x -2 = 11·6 -2 = 64 = 18+46 . . . answer is correct
The angle adjacent to angle 6 is the one we need to find first. To do this, add the measures of the intercepted arcs and divide by 2. 60 + 50 = 110, and half of that is 55. That means that both adjacent angles to the angle 6 are 55 (vertical angles are congruent). The measure of all the angles added together is 360 and angle 6 is vertical to the other "sideways" angle, so they are congruent as well. 360 - 55 - 55 = 250. Split that up between angle 6 and its vertical angle to get that each of those measure 125. Angle 6 measures 125, choice b from above.
• P is the principal amount, $3000.00.
• r is the interest rate, 6% per year, or in decimal form, 6/100=0.06.
• t is the time involved, 8 years time periods.
• So, t is 8 year time periods.
To find the simple interest, we multiply 3000 × 0.06 × 8 to get that:
The interest is: $1440.00
Idk exactly what your question is asking, but I think you are doing genetics? If you are then you are talking about a punnet square. All four boxes should be heterozygous(Cc). Hope this helps.
