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Sever21 [200]
3 years ago
10

What type of Organism depends on auto transfer energy and carbon compounds

Biology
1 answer:
Dmitry [639]3 years ago
5 0

Heterotrophs

Explanation:

Heterotrophs are organisms that depends on autrotrophs to transfer energy and their carbon compounds.

Heterotrophs are plants and animals that are not capable of producing their own food on their own. They depend on mostly plant materials and products for their own nourishment.

  • Organisms that are able to produce their own food are called autotrophs.
  • Autotrophs takes up raw materials from the environment and manufacture their own food.
  • Autotrophs can be photosynthetic or chemosynthetic.
  • Autrotrophs are producers in the food chain or web.
  • Heterotrophs are consumers at all level. They depend on the materials produced by the autotrophs for their own survival and nourishment.

learn more:

Autotrophs brainly.com/question/3150299

#learnwithBrainly

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What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow
Slav-nsk [51]

Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u>f_b_i_c_e_p_s<u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u>f_e_l_b_o_w<u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps f_b_i_c_e_p_s -

Mass of the forearm=

m_f=1.50kg

Mass of the ball =

m_b_a_l_l=950g

   = 0.950kg

so, weight of the forearm=

w_f=m_f g

weight of the ball=

w_b_a_l_l=m_b_a_l_l g

Now , balancing torque about the elbow , we have-

F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36

F_b_i_c_e_p_s=218.38N

Now, lets calculate the force exerted by elbow F_e_l_b_o_w -

Balancing the vertical forces

F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l

F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)

F_e_l_b_o_w=194.37N

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