When the balanced force is applied on the ball It will roll away from the force.
<u>Explanation:</u>
- A ball lies on the floor in rest. If the balanced force is applied to
the ball, the force will push away.
- The forces would include gravity and the forces of air particles entering the ball from almost all directions.
- And the ground is exercising the force and shifting away from the impact.
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Answer:
Initial velocity =
b) Height it reaches = 44.145 m
Explanation:
Using the first equation of motion we have

here
v is the final velocity
u is the initial velocity
a is the acceleration of the object
t is time
When the ball reaches it's highest point it's velocity will become 0 as it will travel no further
Also the acceleration in our case is acceleration due to gravity (
) as the ball moves in it's influence alone with '-' indicating downward direction
Thus applying the values we get

b)
By 3rd equation of motion we have

here s is the distance covered
Applying the value of u that we calculated we get

Answer:
Magnitude of the force is 2601.9 N
Explanation:
m = 450 kg
coefficient of static friction μs = 0.73
coefficient of kinetic friction is μk = 0.59
The force required to start crate moving is
.
but once crate starts moving the force of friction is reduced
.
Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie
.
Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.
Magnitude of the force

The input force will increase too because the more the ramp is increasing the more force is being put on the object going down the ramp... hope this helps ^-^