Answer:
Dy = 111.66 [m]
t = 3.5 [s]
Explanation:
To solve this problem we must use the equations of kinematics.

where:
Vf = final velocity [m/s]
Vo = initial velocity = 27 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time = 3.5 [s]
Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction
Vf = 27 - (9,81*3,5)
Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)
To find how high the snowball was we must use the following equation:

Dy = (27*3.5) + (0.5*9.81*3.5)
Dy = 94.5 + (17.16)
Dy = 111.66 [m]
So, the initial altitude of the parachuter is approximately <u>(C). 123 m</u>.
<h2>Introduction</h2>
Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the following equations apply:
<h3>The equation for calculating the height (h)</h3>

<h3>The equation for calculating the time (s)</h3>

<h3>The equation for calculating the velocity (v)</h3>

With the following condition :
- t = interval of the time (s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
- v = velocity (m/s)
<h2>Problem Solving</h2>
We know that :
- t = interval of the time = 5 s
- g = acceleration of the gravity = 9.81 m/s²
What was asked :
- h = height or displacement at vertical line = ... m
Step by Step :




<h3>Conclusion</h3>
So, the initial altitude of the parachuter is approximately 123 m (C.)
<h3>See More</h3>