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Yuri [45]
3 years ago
8

Antoine Henri Becquerel discovered radioactivity when he was studying

Chemistry
2 answers:
Katen [24]3 years ago
5 0

Antoine Henri Becquerel discovered radioactivity when he was studying

X- rays.  

He had been studying phosphorescent uranium ores and hypothesized that they might absorb sunlight and reemit it as X-rays.

His hypothesis was wrong, but his experiments led to the discovery of <em>natural radioactivity</em>.

Gemiola [76]3 years ago
3 0

X-Rays is the answer

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What mass of Al contains the same number of atoms as 33.5g of Au
wel
Stoich questions...

1) convert the grams of Au to moles
(33.5g)/(196.7g/mol)=___x___

2)find how many atoms are in that many moles by multiplying it by avogadro's number.

x(moles of Au)*(6.02*10^23)=?

3)now that you have found the number of atoms of gold, convert it to grams of aluminum by multiplying it by Avogadro's number and multiplying it by the atomic mass of aluminum.
( ? )(6.02*10^23)(26.98g/mol)= (mass of Al)

5 0
3 years ago
Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas
hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Suppose 1.20 mol CS_2(g) of and 3.60 mol of Cl_2(g)  were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol  of CCl_4. Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of  CS_2 = 1.20 mole

Moles of  Cl_2 = 3.60 mole

Volume of solution = 1.00  L

Initial concentration of CS_2 = \frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M

Initial concentration of Cl_2 = \frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M

The given balanced equilibrium reaction is,

                 CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Initial conc.         1.20 M        3.60 M                  0                  0

At eqm. conc.     (1.20-x) M   (3.60-3x) M   (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}

Now put all the given values in this expression, we get :

K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}

Given :Equilibrium concentration of CCl_4 , x = \frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M

K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}

K_c=0.36

Thus equilibrium constant at unknown temperature is 0.36

4 0
2 years ago
How many electrons are in the nucleus of an atom with an atomic number of 7?!!
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There are two electrons
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3 years ago
Why do you think most lampshades are made of translucent materials instead of transparent materials?
Gala2k [10]

Explanation:

because translucent shades lets the light through easily (gentle diffusion)

6 0
2 years ago
20 mL of 80°C water is mixed with 20 mL of 0°C water in a perfect calorimeter. What is the final temperature?
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Times it bye for then ur answer will be 80
5 0
2 years ago
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