Answer:
Independent variable: different alcohols
Dependent variable: red dye
Answer:
ethanol is already at the ethanol's boiling point: (0.826 kJ/g) x (70.05 g) = 57.8613 kJ = 5.79 x 10^4 J.
Missing: 45.65 | Must include: 45.65
Explanation:
Answer:
Explanation:
We have to make 100 mL 0f .405M HCl from 3 M solution of HCl .
volume of 3M to be taken required . Let this volume be V litre .
V litre of 3M will contain 3 V moles of HCl .
moles contained by 100 mL of ,405 HCl = .405 x .1 = .0405 moles .
So 3V = .0405
V = .0405 / 3 litre
= .0405 x 1000 / 4 mL
= 10.125 mL
So we have to take 10.125 mL of 3M HCl and add water to them to make its volume 100 mL .
Answer:
On the attached picture
Explanation:
Hello,
As long as the addition of the Tollen's reagent turn out in to the oxidation of the aldehyde, the formed product will be its corresponding carboxylic acid, this is 3-methylbutanoic acid whose structure is shown on the attached picture in the form of the oxidation reaction.
Best regards.
Answer:
6.95 x 10²³ molecules/particles
Explanation:
First we need to find the total Empirical Mass. We can find this by adding each element's mass together.
Al = 26.982,
O = 15.999
H = 1.008
26.982 + 3(15.999) + 3(1.008) = 78.003.
Now we divide by the mass given (90 grams).
90/78.003 = 1.153801777.
We then take that number and multiply it by avogadro's number (6.022 x 10²³)
1.153801777 x avogadro's number = 6.95 x 10²³