Answer: 40.3 L
Explanation:
To calculate the moles :
According to stoichiometry :
1 moles of produces = 3 moles of
Thus 0.600 moles of will produce=
of
Volume of
Thus 40.3 L of CO is produced.
a sample of sucrose was burned in a calorimeter, and 41,600 joules oh heat energy were released. which statement is true about t
1 answer:
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Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L
Explanation:
According to ideal gas equation:
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 0.684
R = gas constant =
T =temperature = (at STP)
Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L