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kow [346]
3 years ago
10

Which of the following is an example of symbiosis?

Chemistry
2 answers:
KengaRu [80]3 years ago
5 0
D. One chimp cleaning and grooming the hair of another chimp
Elenna [48]3 years ago
3 0

Answer:

c

Explanation:

im doing it now and the answer above me is wrong

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A quantity of 200 mL of 0.862 M HCl (aq) is mixed with 200 mL of 0.431
Agata [3.3K]

Answer:

The answer to this question has been described in details on the screenshots attached to this question.

Thanks. Hope it helps

7 0
3 years ago
Object A has a mass of 500g and object B has a mass of 300g. Which object is more dense?
KonstantinChe [14]

Answer:

500g because 300g is less dense than 500g its kinda like a weight

Explanation:

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4 0
3 years ago
What is the electron configuration for La (lanthanum)?
MrRissso [65]

Answer:

Lathanum .

Atomic number = 57

Symbol = La

Atomic weight = 138.9

No of energy orbitals = 6

Electronic configuration

[Xe]6s^25d^1

7 0
3 years ago
A sample of 0.200 moles of nitrogen occupies 0.400 L. Under the same conditions, what number of moles occupies 1.200 L
IRISSAK [1]

The number of mole of nitrogen that occupies 1.2 L under the same condition is 0.6 mole

<h3>Data obtained from the question </h3>
  • Initial mole (n₁) = 0.2 mole
  • Initial volume (V₁) = 0.4 L
  • Final volume (V₂) = 1.2 L
  • Final mole (n₂) =?

<h3>How to determine the final mole </h3>

The final mole can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side n

PV / n = RT

Divide both side by P

V / n = RT / P

RT / P = constant

V / n = constant

Thus,

V₁ / n₁ = V₂ / n₂

0.4 / 0.2 = 1.2 / n₂

2 = 1.2 / n₂

Cross multiply

2 × n₂ = 1.2

Divide both side by 2

n₂ = 1.2 / 2

n₂ = 0.6 mole

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

7 0
2 years ago
Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass o
marusya05 [52]
<span>The weight of the precipitate was 17.550g - 17.410g = 0.140g. From a 10ml sample, this means the concentration was 0.140g / 10ml, which is equal to 0.014g/ml.</span>
6 0
3 years ago
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