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True [87]
4 years ago
10

3C2H402 atoms in formula

Chemistry
1 answer:
Vanyuwa [196]4 years ago
4 0
3( 2 carbons + 4 hydrogen's + 2 oxygens)

3*(8) = 24
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What is the pH of a solution that contains 0.009 grams of oxalic acid in 100<br> mL of water?
tigry1 [53]

Answer:

pH = 3.0 ya that's it......

5 0
3 years ago
How many electrons are in na+1
andrew11 [14]

Answer:

10

Explanation:

Sodium has 11 electrons when it is neutral. This sodium isn't neutral, it has a +1 charge. The +1 charge means it has lost 1 electron.

11 - 1 = 10

8 0
4 years ago
Read 2 more answers
Calculate the volume in litres (L) of 1.41 mol of gas at 68.0 kPa and 27.00 °C (gas constant R = 8.314 J mol K-.).
Pani-rosa [81]

Answer:

3.) 51.7 L

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In the equation,

-----> P = pressure (kPa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (8.314 kPa*L/mol*K)

-----> T = temperature (K)

First, you need to convert the temperature from Celsius to Kelvin. Then, you can plug the given values into the equation and simplify to find "V".

P = 68.0 kPa                          R = 8.314 kPa*L/mol*K

V = ? L                                    T = 27.00 °C + 273 = 300 K

n = 1.41 moles

PV = nRT                                                              <----- Ideal Gas Law

(68.0 kPa)V = (1.41 moles)(8.314 kPa*L/mol*K)(300 K)      <----- Insert values

(68.0 kPa)V = 3516.822                                      <----- Multiply right side

V = 51.7                                                                <----- Divide both sides by 68.0

3 0
1 year ago
If a sample of HF gas at 694.9 mmHg has a volume of 3.463 Land the volume is changed to 5.887 L, then what will be the new press
VARVARA [1.3K]

Answer:

\large \boxed{\text{381.7 mmHg}}

Explanation:

Data:

p₁ = 694.9 mmHg; V₁ = 3.463 L

p₂ = ?;                     V₂ = 5.887 L

Calculation:

\begin{array}{rcl}p_{1}V_{1} & = & p_{2}V_{2}\\\text{648.9 mmHg} \times \text{3.463 L} & = & p_{2} \times\text{5.887 L}\\\text{2247.1 mmHg} & = & 5.887p_{2}\\p_{2} & = & \dfrac{\text{2247.1 mmHg}}{5.887}\\\\& = &\textbf{381.7 mmHg}\\\end{array}\\\text{The new pressure of the gas is $\large \boxed{\textbf{381.7 mmHg}}$}

4 0
3 years ago
About one-third of the toxic metal, mercury (Hg), is released into the air from natural sources, such as rocks, soil, volcanoes,
Stolb23 [73]

Answer:

Two-third of the toxic metal, mercury comes from gold mining.

Explanation:

During gold mining small pieces of gold which are within  the soil are separated with the help of mercury. Both gold and mercury are mixed and they forms amalgam. Further gold can be extracted by vaporizing the mercury, thus releasing it into air and contributing to two-third of the air pollution by human activities.

Therefore (d) gold mining is the correct answer.

7 0
3 years ago
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