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alexandr1967 [171]
3 years ago
7

Which reaction has a positive δs°? question 6 options:

Chemistry
1 answer:
Nastasia [14]3 years ago
3 0
B. Because there are 3 molecules in right and 2 molecules in the left, so entropy rises.
You might be interested in
On the basis of the expected charges on the monatomic ions, give the chemical formula of each of the following compounds: (a) ma
lakkis [162]

Answer:

(a) magnesium arsenide: As₂Mg₃

(b) indium(III) sulfide: In₂S₃

(c) aluminum hydride: AlH₃

(d) hydrogen telluride: H₂Te

(e) bismuth(III) fluoride: BiF₃

Explanation:

(a) magnesium arsenide:

The expected oxidation states are-

Magnesium ion- Mg²⁺

Arsenide ion- As³⁻

The chemical formula is: As₂Mg₃

(b) indium(III) sulfide:

The expected oxidation states are-

Indium ion- In³⁺

Sulfide ion- S²⁻

The chemical formula is: In₂S₃

(c) aluminum hydride:

The expected oxidation states are-

Aluminium ion- Al³⁺

Hydride ion- H⁻

The chemical formula is: AlH₃

(d) hydrogen telluride:

The expected oxidation states are-

Hydrogen - H⁺

telluride ion- Te²⁻

The chemical formula is: H₂Te

(e) bismuth(III) fluoride:

The expected oxidation states are-

bismuth ion- Bi³⁺

fluoride ion- F⁻

The chemical formula is: BiF₃

5 0
3 years ago
[1] b) In a local election there were 8000 registered voters. Of these 3200 voted. What was the percentage that voted? [1] <​
Alexandra [31]

Answer:

40% of registered voters voted

Explanation:

3200 out of 8000,

or :

3200 / 8000

= 0.4

0.4 x 100 = 40

40% of registered voters voted

4 0
2 years ago
For the following reaction, 35.4 grams of zinc oxide are allowed to react with 6.96 grams of water . zinc oxide(s) + water(l) --
IRISSAK [1]

Answer:

m_{Zn(OH)_2}=38.4g

Explanation:

Hello!

In this case, for the undergoing chemical reaction:

ZnO(s)+H_2O(l)\rightarrow Zn(OH)_2

We evaluate the yielded moles of zinc hydroxide by each reactant as shown below:

n_{Zn(OH)_2}^{by ZnO}=35.4gZnO*\frac{1molZnO}{81.38gZnO}*\frac{1molZn(OH)_2}{1molZnO}  =0.435molZn(OH)_2\\\\n_{Zn(OH)_2}^{by H_2O}=6.96gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molZn(OH)_2}{1molH_2O}  =0.386molZn(OH)_2

In such a way, since the water yields a smaller amount of zinc hydroxide we conclude it is the limiting reactant so the maximum mass is computed below:

m_{Zn(OH)_2}=0.386molZn(OH)_2*\frac{99.424 gZn(OH)_2}{1molZn(OH)_2} \\\\m_{Zn(OH)_2}=38.4g

Because the water limits the yielded amount of zinc hydroxide.

Best regards!

5 0
3 years ago
Answer the following questions about the solubility of AgCl(s). The value of Ksp for AgCl(s) is 1.8 × 10−10.
Firlakuza [10]

Answer:

  • [Ag⁺] = 1.3 × 10⁻⁵M
  • s = 3.3 × 10⁻¹⁰ M
  • Because the common ion effect.

Explanation:

<u></u>

<u>1. Value of [Ag⁺]  in a saturated solution of AgCl in distilled water.</u>

The value of [Ag⁺]  in a saturated solution of AgCl in distilled water is calculated by the dissolution reaction:

  • AgCl(s)    ⇄    Ag⁺ (aq)    +    Cl⁻ (aq)

The ICE (initial, change, equilibrium) table is:

  • AgCl(s)    ⇄    Ag⁺ (aq)    +    Cl⁻ (aq)

I            X                      0                    0

C          -s                      +s                  +s

E         X - s                   s                     s

Since s is very small, X - s is practically equal to X and is a constant, due to which the concentration of the solids do not appear in the Ksp equation.

Thus, the Ksp equation is:

  • Ksp = [Ag⁺] [Cl⁻]
  • Ksp = s × s
  • Ksp = s²

By substitution:

  • 1.8 × 10⁻¹⁰ = s²
  • s = 1.34 × 10⁻⁵M

Rounding to two significant figures:

  • [Ag⁺] = 1.3 × 10⁻⁵M ← answer

<u></u>

<u>2. Molar solubility of AgCl(s) in seawater</u>

Since, the conentration of Cl⁻ in seawater is 0.54 M you must introduce this as the initial concentration in the ECE table.

The new ICE table will be:

  • AgCl(s)    ⇄    Ag⁺ (aq)    +    Cl⁻ (aq)

I            X                      0                  0.54

C          -s                      +s                  +s

E         X - s                   s                     s + 0.54

The new equation for the Ksp equation will be:

  • Ksp = [Ag⁺] [Cl⁻]
  • Ksp = s × ( s + 0.54)
  • Ksp = s² + 0.54s

By substitution:

  • 1.8 × 10⁻¹⁰ = s² + 0.54s
  • s² + 0.54s - 1.8 × 10⁻¹⁰ = 0

Now you must solve a quadratic equation.

Use the quadratic formula:

     

     s=\dfrac{-0.54\pm\sqrt{0.54^2-4(1)(-1.8\times 10^{-10})}}{2(1)}

The positive and valid solution is s = 3.3×10⁻¹⁰ M ← answer

<u>3. Why is AgCl(s) less soluble in seawater than in distilled water.</u>

AgCl(s) is less soluble in seawater than in distilled water because there are some Cl⁻ ions is seawater which shift the equilibrium to the left.

This is known as the common ion effect.

By LeChatelier's principle, you know that an increase in the concentrations of one of the substances that participate in the equilibrium displaces the reaction to the direction that minimizes this efect.

In the case of solubility reactions, this is known as the common ion effect: when the solution contains one of the ions that is formed by the solid reactant, the reaction will proceed in less proportion, i.e. less reactant can be dissolved.

3 0
2 years ago
An unknown compound a has the molecular formula c7h14o2. compound a absorbs strongly in the ir at 1700 cm-1. the 1h nmr spectral
scoundrel [369]
The structure of compound A would be solid that is dense enough for antimicrobial form
7 0
3 years ago
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