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Contact [7]
3 years ago
13

What is the value of x if one side is 8 and the other side is 6

Physics
1 answer:
scoundrel [369]3 years ago
4 0
X = 2 
hope this helps
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Answer: Your using your skeletal muscle

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Which term best describes a test used to answer a question?
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A) experiment. Is the answer.

hypothesis is the educated guess about what the result of the experiment is before conducting the experiment.

Observation is what you see and record during the experiment.

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What's the definition energy?​
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Energy is the quantitative property that must be transferred to an object in order to perform work on, or to heat, the object.
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Two friends leave a movie theater and take different busses to the same ice cream shop. one bus takes a longer route driving on
irinina [24]

The friend who has the greater displacement is the one who takes the longest path.

<h3>What is displacement?</h3>

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

Given, two friends leave a movie theater and take different buses to the same ice cream shop. One bus takes a longer route driving on a high-speed highway, while the other takes a shorter route on lower-speed local roads.

According to the definition. the displacement is neither larger not shorter but it is the shortest distance traveled by the person or particle.

Thus, friend who has longer path has larger displacement.

Learn more about displacement.

brainly.com/question/11934397

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8 0
2 years ago
Two balls of clay, with masses M1 = 0.49 kg and M2 = 0.47 kg, are thrown at each other and stick when they collide. Mass 1 has a
malfutka [58]

Answer:

a) p_i=1.568\hat{i}+0.752 \hat{j}

b) v_{fx}=1.668\ m.s^{-1}

c) v_{fy}=0.7999\ m.s^{-1}

Explanation:

Given masses:

m_1=0.49\ kg

m_2=0.47\ kg

Velocity of mass 1, v_1=3.2 \hat{i}\ m.s^{-1}

Velocity of mass 2, v_2=1.6 \hat{j}\ m.s^{-1}

a)

Initial momentum:

p_i=m_1.v_1+m_2.v_2

p_i=0.49\times 3.2 \hat{i}+0.47\times 1.6 \hat{j}

p_i=1.568\hat{i}+0.752 \hat{j}

b)

magnitude of initial momentum:

p_i=\sqrt{1.568^2+0.752 ^2}

p_i=1.739\ kg.m.s^{-1}

From the conservation of momentum:

p_f=p_i

m_f.v_f=1.739

v_f=\frac{1.739}{0.49+0.47}

v_f=1.85\ m.s^{-1} is the magnitude of final velocity.

Direction of final velocity will be in the direction of momentum:

tan\theta=\frac{0.752 }{1.568}

\theta=25.62^{\circ}

\therefore v_{fx}=1.85\ cos25.62^{\circ}

v_{fx}=1.668\ m.s^{-1}

c)

Vertical component of final velocity:

v_{fy}=1.85\ sin 25.62^{\circ}

v_{fy}=0.7999\ m.s^{-1}

6 0
3 years ago
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