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4 years ago

Help me please!!!!!!!!!!!!!

Mathematics

1 answer:

AnnZ [28]4 years ago

8 0

For this case the vertex of the parabola is the point at which the parabola presents a minimum.

The parabola presents a minimum in this case, because the parabola opens upwards.

The vertex is then a minimum.

The vertex of the function is located in the following ordered pair:

(x, y) = (1, -1)

Answer:

(x, y) = (1, -1)

minimum

Option A

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mafiozo [28]

Answer:

20 Km per hour.

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3 years ago

The mean survivial time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years. Based on a parti

frutty [35]

Answer:

The time the patient expected to survive after diagnosis is 29 years.

Step-by-step explanation:

It is provided that the mean survival time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years.

That is,

$\mu=15\\\sigma=5$

An individual's predicted survival time is <em>a</em> = 2.8 standard deviations beyond the mean.

Compute the time the patient expected to survive after diagnosis as follows:

$X=\mu+a\sigma$

$=15+(2.8\times 5)\\\\=15+14\\\\=29$

Thus, the time the patient expected to survive after diagnosis is 29 years.

5 0

3 years ago

Draw TWO lines in each 90 degree angle, cutting each 90 into three equal angles.

Serga [27]

Answer:

I think the circles would be cut into eighths then.

Step-by-step explanation:

I hope this helps you! :D

3 0

3 years ago

Use fundamental theorem of calculus to find derivative of the function LOOK AT PHOTO

kykrilka [37]

Let c > 0. Then split the integral at t = c to write

$f(x) = \displaystyle \int_{\ln(x)}^{\frac1x} (t + \sin(t)) \, dt = \int_c^{\frac1x} (t + \sin(t)) \, dt - \int_c^{\ln(x)} (t + \sin(t)) \, dt$

By the FTC, the derivative is

$\displaystyle \frac{df}{dx} = \left(\frac1x + \sin\left(\frac1x\right)\right) \frac{d}{dx}\left[\frac1x\right] - (\ln(x) + \sin(\ln(x))) \frac{d}{dx}\left[\ln(x)\right] \\\\ = -\frac1{x^2} \left(\frac1x + \sin\left(\frac1x\right)\right) - \frac1x (\ln(x) + \sin(\ln(x))) \\\\ = -\frac1{x^3} - \frac{\sin\left(\frac1x\right)}{x^2} - \frac{\ln(x)}x - \frac{\sin(\ln(x))}x \\\\ = -\frac{1 + x\sin\left(\frac1x\right) + x^2\ln(x) + x^2 \sin(\ln(x))}{x^3}$

8 0

2 years ago

A soccer tournament starts out with 128 teams after each round half of the teams are eliminated after 6 rounds how many are left

victus00 [196]

128/2^x x being the number of rounds.
128/2^6
128/64
2
2 teams are left at the 6th round.

8 0

3 years ago

Read 2 more answers