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Darya [45]
3 years ago
5

Two spheres are cut from a certain uniform rock, One has radius 4.85 cm. The mass of the other is three times greater. Find its

radius.
Physics
1 answer:
Alex73 [517]3 years ago
6 0

Answer:7 cm

Explanation:

Given

one sphere has a radius(r) of 4.85 cm

Also another sphere has a mass 3 times the previous one

since the density remains same therefore

second sphere has a volume 3 times of former.

Let R be the radius of bigger Sphere

\frac{4\pi R^3}{3}=3\times \frac{4\pi r^3}{3}

R=\left ( 3\right )^\frac{1}{3}r=1.44\times 4.85=6.99 \approx 7 cm

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Answer:

17.2 seconds

Explanation:

Given:

v₀ = 0 m/s

a₁ = 10.0 m/s²

t₁ = 3.0 s

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t₂ = 5.0 s

a₃ = -12 m/s²

v₃ = 0 m/s

Find: t

First, find v₁:

v₁ = a₁t₁ + v₀

v₁ = (10.0 m/s²) (3.0 s) + (0 m/s)

v₁ = 30 m/s

Next, find v₂:

v₂ = a₂t₂ + v₁

v₂ = (16 m/s²) (5.0 s) + (30 m/s)

v₂ = 110 m/s

Finally, find t₃:

v₃ = a₃t₃ + v₂

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t₃ = 9.2 s

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4 0
3 years ago
A particle starts from the origin at t = 0 with an initial velocity of 4.8 m/s along the positive x axis.If the acceleration is
tia_tia [17]

Answer:

Part a)

Velocity = 6.9 m/s

Part b)

Position = (3.6 m, 5.175 m)

Explanation:

Initial position of the particle is ORIGIN

also it initial speed is along +X direction given as

v_x = 4.8 m/s

now the acceleration is given as

\vec a = -3.2 \hat i + 4.6 \hat j

when particle reaches to its maximum x coordinate then its velocity in x direction will become zero

so we will have

v_f = v_i + at

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Part a)

the velocity of the particle at this moment in Y direction is given as

v_f_y = v_i + at

v_f_y = 0 + 4.6(1.5)

v_f_y = 6.9 m/s

Part b)

X coordinate of the particle at this time

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x = 3.6 m

Y coordinate of the particle at this time

y = v_y t + \frac{1}{2}a_y t^2

y = 0(1.5) + \frac{1}{2}(4.6)(1.5^2)

y = +5.175 m

so position is given as (3.6 m, 5.175 m)

5 0
4 years ago
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