Relative to some reference points,your nose is in motion when you run. relative to others, it is not in motion. give one example
1 answer:
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Answer:
()=1913.31 N/m^2
Explanation:
given:
=0.85
=90 m/s
γ∞=1.23 kg/m^3
solution:
since outside pressure is atm pressure vaccum can be defined by ()
=√2(
)/γ∞[
-1]
()=1913.31 N/m^2
Explanation:
It is given that,
Total mass is 70 kg
The truck exerts a constant force of 20 N.
Then the net force is given by :
F = ma
a is acceleration of rider
Initial velocity of rider is 0. So, using equation of kinematics to find the final velocity as :
Since, 1 m/s = 2.23 mph
4.28 m/s = 9.57 mph
So, the speed of the rider is 4.28 m/s or 9.57 mph.
Answer:
Explanation:
given,
tuning fork vibration = 508 Hz
accelerates = 9.80 m/s²
speed of sound = 343 m/s
observed frequency = 490 Hz
distance the tunning fork has fallen
=8.1 m
now, time required for the observed will be
now, for the distance calculation
=0.293 m
total distance
= 8.1 + 0.293 = 8.392 m