Question

To assess Mendel’s law of segregation using tomatoes, a true-breeding tall variety (SS) is crossed with a true-breeding short variety (ss). The heterozygous F1 tall plants (Ss) were crossed to produce two sets of F2 data, as follows.Set I= 63 tall, 16 short Set II= 630 tall, 160 shortPart A What is the chi square value for Set I?

Answer 1

Answer:

0.949367 ≈ 0.95.

Explanation:

The chi square analysis can be done by the formula as follows:

Chi square = (O-E)²/E

Here, O is observed value and E is expected value.

The tall trait follows the Mendel's law, this means the cross between F1 results in the formation of progeny with ratio 3( tall) : 1 (short).

The observed values for set I is  63 tall, 16 short.

The expected value for tall plant =  $\frac{3}{4}\times79$ = 59.25 .

The expected value for short plant = $\frac{1}{4}\times79$ = 19.75.

Put these value in the formula for chi square analysis:

For tall plants = ( 63 - 59.25)²/ 59.25= 0.237.

For short plants = (16 - 19.75)²/ 19.75 = 0.712

Total value for set I = 0.237 + 0.712 = 0.95.

Thus, the answer is 0.95.