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4 years ago

Explain how the system of the flask and the balloon illustrates the conservation of mass.

1 answer:

4 0

Both containers prevent the escape of matter of the reaction into an uncontrolled space, therefore it is a closed system (not isolated, since energy can still go in and out).

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Air enters a diffuser witha velocity of 400 m/s, a pressure of 1 bar and temperature of 25 C. It exits with a temperature of 100

ANEK [815]

Answer:

Exit velocity of air is 96.43 m/s.

Explanation:

Given that

$V_1=400\ m/s$

$T_1=25C$

$T_2=100C$

For air

$C_p=1.005\ KJ/kg.K$

Now from first law of thermodynamics for open system at steady state

$h_1+\dfrac{V_1^2}{2000}+Q=h_2+\dfrac{V_2^2}{2000}+w$

For diffuser

$h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}$

We know that

$h=C_pT$

$h_1+\dfrac{V_1^2}{2}=h_2+\dfrac{V_2^2}{2000}$

$1.005\times 25+\dfrac{400^2}{2000}=1.005\times 100+\dfrac{V_2^2}{2}$

$V_2=96.43\ m/s$

So the exit velocity of air is 96.43 m/s.

8 0

4 years ago

How many electrons are there in Br−?

Verizon [17]

Total electrons in Bromine(Br) = 35

Plus one -ve ion = 35+1 = 36

7 0

3 years ago

For a gaseous carbon atom in its' ground state which of the following are possible sets of quantum numbers for two different ele

MAXImum [283]

Answer:

Option e=>

electron 1; n l ml ms = 2 1 0 +1/2.

electron 2;n l ml ms= 2 1 -1 +1/2.

Explanation:

The electronic configuration of carbon in its ground state is 1s2 2s2 2p2. The excited electronic configuration of carbon is given as; 1s2 2s1 2p3 because one of the electrons moves to the 2p sub- orbital because of the absorption of the atom.

Recall that there are four different types of quantum numbers and they are the principal quantum number,n; the Azimuthal quantum number, l; the magnetic quantum number, ml and the spin quantum number, Ms.

Our principal quantum number,n is TWO(2) which is the highest energy level from the electronic configuration written above.

The Azimuthal quantum number is 1 from l= n - 1.

The magnetic quantum number is -1 and 0 because we have two electrons filling the 3 orbitals of 2p sublevels. That is;

2px = -1 , 2py = 0 and 2pz = +1.

Only 2px and 2py will be considered because we have 2 electrons on the 2p in the ground state electronic configuration.

Therefore, the first electron will have ml= 0 and the second electron will have ml= -1.

Spin quantum number, ms; in both electrons the spins is an up spin so we have a +1/2 for both electron.

Hence; electron 1; n l ml ms = 2 1 0 +1/2.

Electron 2;n l ml ms= 2 1 -1 +1/2.

8 0

3 years ago

Consider the balanced equation below.

Bumek [7]

Answer : The correct option is, (2) 8 mole of hydrogen will react with 1 mole of sulfur.

Explanation :

The balanced chemical equation is,

$8H_2+S_8\rightarrow 8H_2S$

By the stoichiometry we conclude that, 8 moles of hydrogen react with 1 mole of sulfur to give 8 moles of hydrogen sulfide.

Hence, the correct options is, (2) 8 mole of hydrogen will react with 1 mole of sulfur.

6 0

3 years ago

Read 2 more answers

Write the Henderson-Hasselbalch equation for a propanoic acid solution ( CH 3 CH 2 CO 2 H CH3CH2CO2H , p K a = 4.874 pKa=4.874 )

scoundrel [369]

The answer & explanation for this question is given in the attachment below.

5 0

3 years ago