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3 years ago

Determine the number of atoms in 1.70 ml of mercury. (the density of mercury is 13.5 g/ml.)

Chemistry

1 answer:

marishachu [46]3 years ago

8 0

<span>To determine the number of atoms in 1.70ml of mercury, we have to determine the moles of mercury.</span>

<span>First find the mass in grams by using the formula:</span>

<span>Mass = volume x density</span>

<span>Now find number of moles;</span>

<span>For number of atoms multiply with Avogardro's number that is 6.023 x 10</span>²³

<span>
<span>(0.1144 mol Hg) x (6.023 x 10</span></span>²³ atoms/mol) = 6.89 x 10²² atoms Hg

So, there is 6.89 x 10²² atoms of mercury are present in 1.70ml of mercury.

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Read 2 more answers

If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of

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This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

$M=\frac{n}{V}$

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

$2.60g*\frac{1mol}{102.89g} =0.0253mol$

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

$M=\frac{0.0253mol}{0.160L}=0.158M$

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

$V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L$

That in milliliters turns out to be:

$V=0.211L*\frac{1000mL}{1L}=211mL$

Learn more about molarity: brainly.com/question/10053901

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