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dsp73
3 years ago
13

Determine the number of atoms in 1.70 ml of mercury. (the density of mercury is 13.5 g/ml.)

Chemistry
1 answer:
marishachu [46]3 years ago
8 0

<span>To determine the number of atoms in 1.70ml of mercury, we have to determine the moles of mercury.</span>

<span>First find the mass in grams by using the formula:</span>

<span>Mass = volume x density</span>

<span>(1.70 mL Hg) x (13.5 g/mL) = 22.95 g Hg </span>

<span>Now find number of moles;</span>

<span>
(22.95 g Hg) x (1 mol Hg/200.59 g/mol) = 0.1144 mol Hg </span>

<span>For number of atoms multiply with Avogardro's number that is 6.023 x 10</span>²³

<span>
<span>(0.1144 mol Hg) x (6.023 x 10</span></span>²³ atoms/mol) = 6.89 x 10²² atoms Hg 

So, there is 6.89 x 10²² atoms of mercury are present in 1.70ml of mercury.

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False is the answer.
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Fe3N2, also known as Iron (II) nitride, is an ionic compound.


Ionic compounds are compounds that consists of metals and non-metals bonded with ionic bonds. The metal ion gives up electron(s) to the non-metals.


Since iron is a metal and nitrogen is an non-metal, the bond they would form would be an ionic bond. Iron gives up 2 electrons to form iron(II) ion, while nitrogen gains 3 electrons to form nitride ion. Since one iron cannot let a nitrogen gain 3 electrons, so in the compound, there would be 3 iron (ii) ions that has given up 6 electrons in total while 2 nitride ions have gained 6 electrons in total.

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3 years ago
2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder
damaskus [11]

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<h2>7.54 atm </h2>

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

P_2 =  \frac{P_1V_1}{V_2}  \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

P_2 =  \frac{1 \times 196}{26}  =  \frac{196}{26}   \\ = 7.538461...

We have the final answer as

<h3>7.54 atm </h3>

Hope this helps you

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Define Nuclear Fission with an example of it​
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8 0
3 years ago
Read 2 more answers
If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of
navik [9.2K]

This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

M=\frac{n}{V}

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

2.60g*\frac{1mol}{102.89g} =0.0253mol

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

M=\frac{0.0253mol}{0.160L}=0.158M

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L

That in milliliters turns out to be:

V=0.211L*\frac{1000mL}{1L}=211mL

Learn more about molarity: brainly.com/question/10053901

6 0
1 year ago
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